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Wewaii [24]
3 years ago
5

5.8×10^−10 ​? Solve please! (Scientific Notation)

Mathematics
2 answers:
worty [1.4K]3 years ago
6 0

5.8x10^-10 is already in sciencific notation. To convert it to normal notation you move the decimal either the right OR left the number of places the exponet says.  This case it is 10, but the negative determines the direction which is left (negative is left and positive is right.)  Thus your answer is 0.00000000058

Dmitry_Shevchenko [17]3 years ago
3 0
First off, we need to understand how scientific notation works, here are some examples:

10^2 = 10x10 = 100, 4^3 = 4x4x4 = 64

10^-1=0.1

10x10^-2 = 10x0.01x0.1 = 0.01, 4x10^-3 = 4x0.1^3 = 4x0.1x0.1x0.1 = 0.004

In this case:

5.8×10^−10

=5.8 x 0.1^10

=5.8 x 0.000000001

=0.00000000058

Hope it helps!
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Kelsey makes pendants that she would like to sell at an upcoming craft fair. She must pay $200 to rent a booth at the craft fair
lubasha [3.4K]

Answer:

Additional <em>26</em> pendants are to be sold to make profit.

Step-by-step explanation:

Rent of booth at the craft fair = $200

Cost of material for each pendant = $7.80

Let Kelsey makes x number of pendants.

To calculate the total spending, we have to add the rent of booth at the craft fair and cost of material for x number of pendants.

Cost of material for x number of pendants = Cost of material for each pendant multiplied by number of pendants

Cost of material for x number of pendants = $7.80 \times x

So, total cost = $200 +  $7.80 \times x

Now, each pendant is sold at $13.50

So, total money made by selling  x pendants =  $13.50 \times x

For making profit, total money made must be greater than the total cost.

Therefore, the inequality becomes:

\bold{13.50 \times x  > 200+7.80\times x }

Let us solve the inequality now:

13.50x - 7.80x>200\\\Rightarrow 5.7x > 200\\\Rightarrow \bold{x > 35.08}

So, at least 36 pendants are to be sold to make a profit.

Additional 36-10  = <em>26</em> pendants are to be sold to make profit.

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Answer:

2) 10/9 = 1.111111111

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Step-by-step explanation:

Hope this helps

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