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Ray Of Light [21]
3 years ago
6

I need help with this question

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

So we have an original figure with a value of 50 and then a scaled version or dilation

Hence we have a scale factor of

\frac{1}{5}

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Thepotemich [5.8K]

Answer:

3/4 pizza is left. If you want an explanation, ask me ;>

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48/50 - 20/25 please Answer this ASAP please
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0.16

Step-by-step explanation:

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2 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
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gogolik [260]

Answer:

B is correct.

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I’m training my robot to eat Ludies cupcakes. Every 4 days it eats 2 cupcakes and I’d like enough for the next 12 days. Thank yo
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I hope your robot enjoyed them cupcakes!
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