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valkas [14]
3 years ago
11

Solve, show all four steps.

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0
3x-6+10x+15=35
10x+3x=35-15+6
13x=26
x=2
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What does y is two less than x stand for
solong [7]

Answer:

Y = X - 2 would be the answer.

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3 years ago
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A polygon that undergoes a series of transformations that the image has the corresponding sides and angles of equal measure to t
Gnoma [55]

What did the answer end up being?

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Solve for u. 31.25 = u/5
ipn [44]

Answer:

u = 156.25

Step-by-step explanation:

Step 1: Write equation

31.25 = u/5

Step 2: Solve for <em>u</em>

  1. Multiply both sides by 5: 156.25 = u
  2. Rewrite: u = 156.25

Step 3: Check

<em>Plug in u to verify it's a solution.</em>

31.25 = 156.25/5

31.25 = 31.25

3 0
3 years ago
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Create your own real-world example of a relation that is a function. Domain: The set of Range: The set of
ivanzaharov [21]

Answer:

C(t)=5000 -10t

Step-by-step explanation:

There are many examples in the real world of relationships that are functions.

For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.

If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:

C(t)=C_{0}-at\\

Where:

C (t): Amount of water in the tank as a function of time

C_{0}: Initial amount of water in the tank at time t = 0

a: amount of water lost per hour

t: time in hours

Then the equation is:

C(t)=5000 -10t

The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.

Its domain is the set of all positive real numbers t between [0,500]

Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty

Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres

7 0
3 years ago
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the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational manuever increased it's dep
tester [92]

Answer:

Position of the submarine now relative to the water surface =-47\ \frac{3}{4}

Step-by-step explanation:

It says that the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational maneuver increased it's depth by 15 1/2 feet.

Now we need to find about what is the position of the submarine now relative to the water surface.

Downward navigation means we 15 1/2 is negative

so we will just add both values to get the final answer:

Position of the submarine now relative to the water surface = -32\ \frac{1}{4}-15\ \frac{1}{2}

=-32\ \frac{1}{4}-15\ \frac{2}{4}

=-47\ \frac{3}{4}


5 0
4 years ago
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