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3 years ago

PLZ HELP!!!!! ASAP!!!!!!!!!!!! NO FILES!

Mathematics

1 answer:

iVinArrow [24]3 years ago

6 0

Answer:

A' (1, -4)

B' (-4, -2)

C' (-5, 4)

D' (-2, 1)

Step-by-step explanation:

When reflecting a point across the x-axis, the x-coordinate remains the same, but the y-coordinate becomes its additive inverse.

The additive inverse of a number is simply the opposite of a number.

So, to reflect this quadrilateral across the x-axis, we must change the coordinates.

Remember: When reflecting a point across the x-axis, the x-coordinate remains the same, but the y-coordinate becomes its additive inverse.

Point A: (1, 4) ⇒ A' (1, -4)

Point B: (-4, 2) ⇒ B' (-4, -2)

Point C: (-5, -4) ⇒ C' (-5, 4)

Point D: (-2, -1) ⇒ D' (-2, 1)

The attachment will help as well.

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Please help vvvvvvvvvvv

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

since you are subtracting a negative number it reverses, so you actually ADD the two together

so, 12 1/2 + 4 1/2

add the whole numbers first;

12+4=16

then fractions:

1/2 + 1/2= 1

then all together;

16+1=17!

7 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Can anyone help me with this? thank you

wel

"MIDDLE OF THE NIGHT"

I summoned you, please come to me

Don't bury thoughts that you really want

I fill you up, drink from my cup

Within me lies what you really want

Come, lay me down

'Cause you know this

'Cause you know this sound

In the middle of the night

Just call my name

I'm yours to tame

In the middle of the night

I'm wide awake

I crave your taste all night long

'Til morning comes

I'm getting what is mine

You gon' get yours, oh no, ooh

In the middle of the night

In the middle of the night, oh

These burning flames, these crashing waves

Wash over me like a hurricane

I captivate, you're hypnotized

Feel powerful, but it's me again

Come, lay me down

'Cause I know this

'Cause I know this sound

In the middle of the night

Just call my name

I'm yours to tame

In the middle of the night

I'm wide awake

I crave your taste all night long

'Til morning comes

I'm getting what is mine

You gon' get yours, oh no, ooh

In the middle of the night

In the middle of the night, oh

Just call on me, ah

Just call my name

Like you mean it, ah

In the middle of the night

Just call my name

I'm yours to tame

In the middle of the night

I'm wide awake

I crave your taste all night long

'Til morning comes

I'm getting what is mine

You gon' get yours, oh

In the middle of the night

In the middle of the night, o

Step-by-step explanation:

5 0

2 years ago

Rename the number 600,000 in ten thousands

telo118 [61]

I think it is 60,000

4 0

3 years ago

You are in a bike race. When you get to the first checkpoint, you are $\frac{2}{5}$

Black_prince [1.1K]

Answer:

The distance from the star to the second checkpoint is 4 miles

Step-by-step explanation:

The complete question in the attached figure

we know that

When you get to the second checkpoint, you are 1/4 of the distance to the finish

The distance from the star to the second checkpoint is equal to the total distance multiplied by 1/4

The total distance is 40 miles ( see the attached figure)

The distance from the star to the second checkpoint is

$\frac{1}{4}(40)=10\ miles$

Find out the distance from the start to the first checkpoint

Multiply the distance from the star to the second checkpoint by 2/5

$\frac{2}{5}(10)=4\ miles$

6 0

3 years ago