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Flura [38]
3 years ago
11

Look at the problem 325 x 89. 1. Write out the six multiplication problems that are involved in solving this problem.​

Mathematics
1 answer:
Oksanka [162]3 years ago
5 0

Answer:

Ok, we have:

325*89.1

Let's decompose this into:

325 = 300 + 25

89.1 = 80 + 9 + 0.1

Then we have the multiplication:

(300 + 25)*(80 + 9 + 0.1)

Let's distribute the multiplication:

300*80 + 300*9 + 300*0.1 + 25*80 + 25*9 + 25*0.1

So now we have 6 multiplications that are a lot easier to solve than the initial one that we had.

Then the list of six multiplications involved in solving this problem are:

300*80 = 24,400

300*9 = 2,700

300*0.1 = 30

25*80 = 2,000

25*9 = 225

25*0.1 = 2.5

Now we add all of those and get:

325*89.1 = 24,400 + 2,700 + 30 + 2,000 +  225 + 2.5 = 28,957.5

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3 years ago
Joan Messineo borrowed ​$47,000 at a 5​% annual rate of interest to be repaid over 3 years. The loan is amortized into three​ eq
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a) The value of the Annual Payment is A=$17,258.80

b) Is the picture in the attachment file

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Step-by-step explanation:

Hi

a) First of all, we are going to list the Knowns: VP=47000, i=5% and n=3, Then we can use A=\frac{VP}{\frac{1-(1+i)^{-n} }{i} } =\frac{47000}{\frac{1-(1+0.05)^{-3} }{0.03} }=17258.80. So this is the value of the Annual Payment

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3 years ago
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3 years ago
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