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lubasha [3.4K]
3 years ago
5

A certain colony of bacteria begin with one cell and the population doubles every 20 minutes. What was the population of The Col

ony after 2 hours?
a. 6
b. 12
c. 32
d. 64​
Mathematics
1 answer:
svetoff [14.1K]3 years ago
3 0
First 20 minutes:1 Second 20:2 Third 20:4 Fourth 20: 8. Fifth 20: 16 Sixth 20: 32. C is your answer
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6) The sum of three consecutive numbers is seventy-eight.
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Answer:

Step-by-step explanation:

In my opinion the three consecutive numbers should be 25 26 and 27

25 + 26 + 27 = 78

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Express the following equation in slope-intercept form: 13x - 3y = 18 Select the best answer from the choices provided. A. y = 3
AveGali [126]

Answer:

The equation in the slope-intercept form is y =  \frac{13}{3}x + -6 ⇒ C

Step-by-step explanation:

The slope-intercept form of the linear equation is

y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept

∵ The equation is 13x - 3y = 18

→ At first move x from the left side to the right side by subtracting 13x

  from both sides

∴ 13x - 13x - 3y = 18 - 13x

∴ - 3y = 18 - 13x

→ Make the coefficient of y equal 1 by dividing both sides by -3

∵ \frac{-3y}{-3}=\frac{18}{-3}-\frac{13x}{-3}

∴ y = -6 - (-\frac{13}{3}x)

→ Remember (-)(-) = (+)

∴ y = -6 + \frac{13}{3}x

→ Switch the two terms of the right side

∴ y =  \frac{13}{3}x + - 6

∴ The equation in the slope-intercept form is y =  \frac{13}{3}x + -6

7 0
3 years ago
A college student Earned $6500 during summer vacation working as a waiter. The student invested Part of the money at 10% and the
Juliette [100K]

Answer:

The amount invested at 10% rate is $ 2200

Step-by-step explanation:

Given as :

The total amount earn by student = $6500

The total interest received at the end of year = $607

Let the amount invested at 10% rate = $x

So, The amount invested at 9% rate = ($6500 - $x)

Let the time for which money invested = 1 year

<u>Now from Simple Interest method :</u>

SI = \frac{principal\times Rate\times Time}{100}

Or, SI_1 + SI_2 = \frac{x\times 10\times 1}{100} + \frac{(6500-x)l\times 9\times 1}{100}

Or, SI_1 + SI_2 = (\frac{10x}{100})+\frac{(6500-x)\times 9}{100}

Or, $607 × 100 = 10x + (6500-x) × 9

Or, $60700 = 10x- 9x + 58500

Or, $60700 - $58500 = x

Or , 2200 = x

∴ x = 2200

So, The amount invested at 10% rate = $x = $ 2200

Hence The amount invested at 10% rate is $ 2200   Answer

5 0
3 years ago
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