A)
Let X be the food expenditure of a family.
Let the population mean of an expenditure of a family be.
Let the population standard deviation of an expenditure of a family be.
The proportion families spend more than $30 but less than $490 per month on food is,
<u>To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.</u>
Answer:
<em>x = -9</em>
<em>y = 2</em>
Step-by-step explanation:
<u>Solve the system:</u>
2x + 3y = -12 [1]
2x + y = -16 [2]
Subtracting [1] and [2]:
3y - y = -12 + 16
2y = 4
y = 4/2 = 2
From [1]:
2x + 3(2) = -12
2x + 6 = -12
2x = -18
x = -18/2 = -9
Solution:
x = -9
y = 2
Answer:
what's the question though??
