Ok well you would use pathagorean there so A2+B2=C2
Answer:
The two diameters that separate the top 5% and the bottom 5% are 5.51 and 5.65 respectively.
Step-by-step explanation:
We are given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.58 millimeters and a standard deviation of 0.04 millimeters.
<em>Let X = diameters of bolts produced in a machine shop</em>
So, X ~ N()
The z score probability distribution is given by;
Z = ~ N(0,1)
where, = mean diameter = 5.58 millimeter
= standard deviation = 0.04 millimeter
<u>Now, we have to find the two diameters that separate the top 5% and the bottom 5%.</u>
- <u>Firstly, Probability that the diameter separate the top 5% is given by;</u>
P(X > x) = 0.05
P( > ) = 0.05
P(Z > ) = 0.05
<em>So, the critical value of x in z table which separate the top 5% is given as 1.6449, which means;</em>
= 1.6449
= 5.58 + 0.065796 = 5.65
<u />
- <u>Secondly, Probability that the diameter separate the bottom 5% is given by;</u>
P(X < x) = 0.05
P( < ) = 0.05
P(Z < ) = 0.05
<em>So, the critical value of x in z table which separate the bottom 5% is given as -1.6449, which means;</em>
= -1.6449
= 5.58 - 0.065796 = 5.51
Therefore, the two diameters that separate the top 5% and the bottom 5% are 5.51 and 5.65 respectively.
The percentage decrease was 13%. If you subtract 1,300,000 from 1,500,000, you will get 200,000. You then divide 200,000 by the original number 1500,000 and you will get 0.13333333333333...
After you do that multiply that number by 100 and you will get your percentage.
(1,500,000-1,300,000=200,000)
(1,500,000/200,000=0.13333333333...)
(0.1333333333333X100=13.33333333...)
and then just round
The length of the midsegment is 22
The value of x in the proportion is 5 and 2/5