-19 to -15 would be a positive 4 difference
19 to 15 = 4 this would be a -4 difference
3 to 7 is a positive 4 difference
-3 to 7 is a difference of 10
so there is 1 with a -4 difference
answer is B.
It has only one solution because it is a linear equation
Hey there
5/12 times 3 = 5/4
5/4 is an improper fraction
so it is changed to <span>= 1 1/4</span>
The answer is 1 1/4
hope this helps you
Hello,
A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)
y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1
eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1
Answer :A--> R,K
B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10
answer B--> I,≈W if it is written -1/2*x² (square has been forgotten)
C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J
D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L
E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!
y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.
y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]
Answer: the mean should not change.
Stabilizing selection: it is one type of the natural selection..
an intermediate variant selected by the nature has more survival rate against extreme and low variants. such variants are well adopted by the population and pass it for several generations without changes. it shows that the mean of the variant <span>will be stabilized for several generations</span>
