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fomenos
3 years ago
13

Solve the following system of equations and show all work. y = 2x^2 +9x y = 4x + 25

Mathematics
1 answer:
Genrish500 [490]3 years ago
7 0

Answer:

x = 5/2 thì y = 35 và x = -5 thì y = 5

Step-by-step explanation:

thay y = 4x + 25 vào phương trình y = 2x ^ 2 + 9x ta có:

4x + 25 = 2x ^ 2 + 9x

⇒2x ^ 2 + 5x - 25 = 0

⇒ x = 5/2 và x = -5

thay x = 5/2 vào phương trình y = 4x + 25 ⇒ y = 4*(5/2) + 25 = 35

thay x = -5 vào phương trình y = 4x + 25 ⇒ y = 4*(-5) + 25 = 5

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Nikolay [14]

Answer: 24 $100 bills, even though this will add up to more than 2324 dollars, it is the amount needed to cover the price

Step-by-step explanation: divide 2324 dollars by 100

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3 years ago
How could i write 2.7 on a number line?
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3 years ago
In a football stadium, 43% of the crowd cheering for Team A, and 52% of the crowd is female. 19% of the crowd is cheering for Te
musickatia [10]
P(TeamA) = 0,43
P(Female) = 0,52
P(TeamA and Female) = 0,19
P(TeamA or Female) = ?

P(TeamA or Female) = P(TeamA) + P(Female) - P(TeamA and Female) <=>

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4 0
3 years ago
How many Solutions does this system have? (1 point)
mixas84 [53]

The given system of equation that is 2x+y=3 and 6x=9-3y has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison

\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}

To check how many solutions are there for system of equations a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0, we need to compare ratios of \frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}

In our case,  

a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3

a_{2}  = 6, b_{2} = 3,\text{ and }c_{2} = -9

\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}

As \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}, so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0
3 years ago
lisa used 880g of a container of sugar to bake a cake and 1/10 of the creaming sugar to make cookies. She then had 3/7 of the co
guapka [62]

Answer:

At the beginning, there were 2,678.26 grams of sugar in the container.

Step-by-step explanation:

Since Lisa used 880g of a container of sugar to bake a cake and 1/10 of the creaming sugar to make cookies, and she then had 3/7 of the container of sugar left, to determine how much sugar was in the container at first, the following calculation must be performed:

880 + 1 / 10X = 3 / 7X

880 + 0.1X = 0.4285X

880 = 0.4285X - 0.1X

880 = 0.3285X

880 / 0.3285 = X

2,678.26 = X

Therefore, at the beginning there were 2,678.26 grams of sugar in the container.

3 0
2 years ago
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