All categories

3 years ago

Solve the following system of equations and show all work. y = 2x^2 +9x y = 4x + 25

Mathematics

1 answer:

Genrish500 [490]3 years ago

7 0

Answer:

x = 5/2 thì y = 35 và x = -5 thì y = 5

Step-by-step explanation:

thay y = 4x + 25 vào phương trình y = 2x ^ 2 + 9x ta có:

4x + 25 = 2x ^ 2 + 9x

⇒2x ^ 2 + 5x - 25 = 0

⇒ x = 5/2 và x = -5

thay x = 5/2 vào phương trình y = 4x + 25 ⇒ y = 4*(5/2) + 25 = 35

thay x = -5 vào phương trình y = 4x + 25 ⇒ y = 4*(-5) + 25 = 5

You might be interested in

How can i solve this?

kenny6666 [7]

Am sorry I try but I cant

6 0

4 years ago

Please help 35 points <br> 100 75 50 25

Tamiku [17]

Answer:

Step-by-step explanation:

every 50 points it takes 1 hr

8 0

3 years ago

Read 2 more answers

Carl button airline ticket two weeks ago the cost of this flight was $300 what is the percent increase

kumpel [21]

3% is the percent increase

8 0

3 years ago

Plz help I need help I don't under stand help on the hole page plzz

Readme [11.4K]

1. > 2.< 3. < 4. < 5. < 6.> (7). 0.31 0.37 0.41 (8) 1.61 1.16 6.11
(9) 7.09 7.91 7.19 7.09 7.9
11. tiger ways the most
12 .sophie weights less
13 is c or d

4 0

4 years ago

Read 2 more answers

Find two positive even consecutive integers such that the square of the smaller integer is 10 more than the larger integer

mafiozo [28]

Answer:

the numbers are $4,6$

Step-by-step explanation:

Let

x-------> the smaller even consecutive integer

x+2-------> the larger even consecutive integer

we know that

$x^{2}=(x+2)+10$

solve for x

$x^{2}-x-12=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-x-12=0$

$a=1\\b=-1\\c=-12$

substitute in the formula

$x=\frac{1(+/-)\sqrt{-1^{2}-4(1)(-12)}} {2(1)}$

$x=\frac{1(+/-)\sqrt{49}} {2}$

$x=\frac{1(+/-)7} {2}$

$x=\frac{1(+)7} {2}=4$ ------> the solution (must be positive)

$x=\frac{1(-)7} {2}=-3$

therefore

the numbers are $4,6$

5 0

3 years ago