Ask question

Ask question

All categories

Neporo4naja [7]

3 years ago

15

Students collected $441 for a donation camp. Each student have as many dollars as there were students. How many students are the

re

1 answer:

Alexandra [31]3 years ago

6 0

Answer:

There are 21 students.

Step-by-step explanation:

If there are 21 students, and each of them had $21 then this would equal a total of $441 because 21 multiplied by 21 equals 441.

Hope this helps,

Trey

You might be interested in

What is x=15 a a function and please explain the process

Vika [28.1K]

<span>Simplifying 15 + 5x = 0 Solving 15 + 5x = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + 5x = 0 + -15 Combine like terms: 15 + -15 = 0 0 + 5x = 0 + -15 5x = 0 + -15 Combine like terms: 0 + -15 = -15 5x = -15 Divide each side by '5'. x = -3 Simplifying x = -3</span>

5 0

3 years ago

Shelby made 5quarts of juice. she said that she made 1 1\4of juice.expkain her mistake

docker41 [41]

Shelby mistake is 11;4 is not the correct mixed number

8 0

3 years ago

Compare the decimals 16.30 and 16.3

pshichka [43]

16.30 and 16.3 equal. If you ever have a problem like that then you just add on a zero.

Example:
19.4500 = 19.45 Just add two zeros on the end
19.45 + two zeros = 1.4500

8 0

3 years ago

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacemen

mamaluj [8]

<h2>Answer:</h2>

(a)

The probability is : 1/2

(b)

The probability is : 1/2

<h2>Step-by-step explanation:</h2>

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2) (1,3) (1,4) (1,5)

(2,1) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,4) (3,5)

(4,1) (4,2) (4,3) (4,5)

(5,1) (5,2) (5,3) (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

We know that it could be calculated by using the formula:

$P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( since, the only outcome out of 20 outcomes is: (3,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

7 0

3 years ago

Ndjdjjxjxjdjfjfjdjjdfjfj

Norma-Jean [14]

Answer:

whh3u2ofefnfek

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers