An ideal scenario for using edge computing solutions is when there is a bad network connection with IoT devices .
<h3>What is Edge computing ?</h3>
Edge computing can be regarded as the process that involves the analyes as well as the, and storage of data closer to where it is generated .
This is been done to enable rapid analysis and response in the process that is been used by some companies to have consolidated operations , hence, An ideal scenario for using edge computing solutions is when there is a bad network connection with IoT devices .
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Answer:
i) The time taken for 1500 records = 15 seconds.
ii) The time taken for 1500 records = 50 seconds.
Explanation:
A is an O(n) algorithm.
An algorithm with O(n) efficiency is described as a linearly increasing algorithm, this mean that the rate at which the input increases is linear to the time needed to compute that algorithm with n inputs.
From the question, it is given that for 1000 records, the time required is: 10 seconds.
Algorithm time taken is O(n)
Hence,
1) For 1,500 records
=> 10/1000 = x/1500
=> 10x1500/1000 = x
x = 15 seconds
Thus, the time taken for 1500 records = 15 seconds.
2) For 5,000 records
=> 10/1000 = x/5000
=> 10x5000/1000 = x
x = 50 seconds
Thus, the time taken for 1500 records = 50 seconds.
She uses the Radio-frequency identification(RFID) which is a technology that uses electromagnetic fields to automatically identify and track tags attached to objects.These tags contain electronically-stored information.the passive tags collect energy from a nearby RFID readers interrogating radio waves.They contain an integrated circuit and an antenna which are used to transmit data to the RFID reader also called an interrogator.
Answer:
False.
Explanation:
Index addressing is not for only traversing the arrays but to also access the element,manipulate them.Though indexing is also used in traversing but it is not solely for that.Indexing in an array starts from 0 to size-1.
for example:-
We have an array a of size 10.So to access the element at position 6.We have to write.
a[5];
Manipulating it
a[5]=6;
