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sineoko [7]
3 years ago
5

Here is the problem specification: An Internet service provider has three different subscription packages for its customers: Pac

kage A: For $9.95 per month 10 hours of access are provided. Additional hours are $2.00 per hour. Package B: For $14.95 per month 20 hours of access are provided. Additional hours are $1.00 per hour. Package C: For $19.95 per month unlimited access is provided. Write a program that calculates a customer's monthly bill. It should ask which package the customer has purchased and how many hours were used. It should then display the total amount due. Input Validation: Be sure the user only selects package A, B or C. Also, the number of hours used in a month cannot exceed 744. Use switch.
Computers and Technology
1 answer:
Andrej [43]3 years ago
6 0

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   int hour; char pkg; float bill = 0;

   cout<<"Package: "; cin>>pkg;

   cout<<"Hour: "; cin>>hour;

   if(hour<=744 && hour >=0){

       switch (pkg) {

           case 'A':

               bill = hour * 9.95;

               if(hour >10){bill = 10 * 9.95 + (hour - 10) * 2;}

           break;

           case 'B':

               bill = hour * 14.5;

               if(hour >10){bill = 20 * 14.5 + (hour - 20) * 1;}

           break;

           

           case 'C':

               bill = 19.95;

           break;

           

           default:

               cout << "Package must be A, B or C";}

cout<<"Total Bills: $"<<bill; }

else{ cout<<"Hour must be 0 - 744"; }

return 0;

}

Explanation:

This declares all variables:    int hour; char pkg; float bill=0;

This prompts the user for package type:  cout<<"Package: "; cin>>pkg;

This prompts the user for number of hours:    cout<<"Hour: "; cin>>hour;

This checks if hour is between 0 and 744 (inclusive)

   if(hour<=744 && hour >=0){

If true, the following is executed

A switch statement to check valid input for package

       switch (pkg) {

For 'A' package

           case 'A':

Calculate the bill

<em>                bill = hour * 9.95;</em>

<em>                if(hour >10){bill = 10 * 9.95 + (hour - 10) * 2;}</em>

End of A package:            break;

For 'B' package

           case 'B':

Calculate the bill

<em>                bill = hour * 14.5;</em>

<em>                if(hour >10){bill = 20 * 14.5 + (hour - 20) * 1;}</em>

End of B package:<em>            </em>break;

For C package            

           case 'C':

Calculate bill:                bill = 19.95;

End of C package:            break;

If package is not A, or B or C

           default:

Prompt the user for valid package                cout << "Package must be A, B or C";}

Print total bills: cout<<"Total Bills: $"<<bill; }

If hour is not 0 to 744: <em>else{ cout<<"Hour must be 0 - 744"; }</em>

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Answer:

Here is code in java.

import java.util.*;

import java.lang.*;

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     else

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  }

  if(lower_c > 0 && upper_c > 0 && non_c > 0) {

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}

}

Explanation:

Declare and initialize two string variables.In the isValidPassword() function, pass the string parameter and then count the lower, upper and non character in the string.If string contains call the three characters then function will return 1 otherwise it will return 0 .

Output:

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output of Pass_word is: 1

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