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Rzqust [24]
3 years ago
7

The carbon dioxide molecule is linear. The electronegativities of C and O are 2.5 and 3.5, respectively. Based on these values a

nd on consideration of molecular geometry, the C-O bond is ________ and the molecule is ________.
Chemistry
2 answers:
masha68 [24]3 years ago
8 0

Answer: Polar; Non-Polar

Dominik [7]3 years ago
4 0

Answer: polar,non polar

Explanation:

The electronegativity of C is 2.5 and of O is 3.5 .The difference in electronegativity(3.5-2.5=1.0) is 1.0 and as per rule if the difference in electronegativity of atoms in a bond is >0.4 then the bond is considered polar. So in this case C-O bond is polar.

However, the symmetrical arrangement of the bonds in the molecule of CO2 makes its non polar.The CO2 molecule is linear so the C-O dipole moment on either side will cancel out each other hence the net dipole moment will be zero.

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In the chart, the organism Rr represents a genetically _____________ individual.
GalinKa [24]
Organism<span>. ' s rate of mutation is directly proportional to its adaptability. .... D. The cell membrane contains </span>genetic<span> information of the cell. .... </span>What<span> cellular structure was the dialysis tubing most likely</span>representing<span> in this experiment? ...... C </span>Rr<span> and </span>rr<span> only ... A healthy </span>individual<span> is a carrier of a lethal allele but is unaffected by it.</span>
4 0
3 years ago
Read 2 more answers
A 34.0 gram sample of an un-known hydrocarbon is burned in excess oxygen to form 93.5 grams of carbon dioxide and 76.5 grams of
natka813 [3]

Answer:

The answer to your question is  CH₄

Explanation:

Process

1.- Write the possible chemical reaction

                   CxHy + O₂   ⇒    CO₂  +   H₂O

2.- Calculate the amount of carbon in the reaction

Molecular mass of CO₂ = 12 + 32 = 44 g

                         44 g of CO₂ ------------------- 12 g of carbon

                         93.5 g of CO₂ ----------------  x

                          x = (93.5 x 12) / 44

                          x = 25.5 g of carbon

3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

                         18 g of water -------------   2 g of hydrogen

                          76.5 g of water --------    x g of hydrogen

                           x = (76.5 x 2) / 18

                           x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

                           12g of carbon ------------- 1 mol

                           25.5g of carbon ---------- x

                             x = (25.5 x 1) / 12

                              x = 2.12 moles of carbon

                            1 g of hydrogen ----------- 1 mol

                            8.5 g of hydrogen -------- x

                             x = (8.5 x 1) / 1

                             x = 8.5 moles of hydrogen

5.- Divide both number of moles by the lowest number

carbon = 2.12 / 2.12 = 1

hydrogen = 2.12 = 8,5 / 2.12 = 4

6.- Write the molecular formula

                                                    CH₄                                        

7 0
3 years ago
Read 2 more answers
The following statements all describe changes in matter. Some of these changes are physical, and some are chemical. Select the s
GenaCL600 [577]

The change of the statue of liberty from copper to green is an example of a chemical change.

<h3>Physical and chemical change</h3>

A physical change does not involve the formation of new substances and the composition of the substance does not change. However, in a chemical change, a new substance is formed and the composition of the substance changes.

The statement that reflect a chemical change is;

  • The Statue of Liberty’s metal tarnishes from copper to green.

Learn more about physical and chemical change: brainly.com/question/13316655

8 0
2 years ago
Arsine, AsH3, is a highly toxic compound used in the electronics industry for the production of semiconductors. Its vapor pressu
lara31 [8.8K]

Answer:

-79.8 × 10⁴ J/mol

Explanation:

<em>Arsine, AsH₃, is a highly toxic compound used in the electronics industry for the production of semiconductors. Its vapor pressure is 35 Torr at 111.95 °C and 253 Torr at 83.6 °C.</em>

<em />

Then,

P₁ = 35 torr

T₁ = 111.95 + 273.15 = 385.10 K

P₂ = 253 torr

T₂ = 83.6 + 273.15 = 356.8 K

We can calculate the standard enthalpy of vaporization (ΔH°vap) using the two-point Clausius-Clapeyron equation.

ln(\frac{P_{2}}{P_{1}} )=\frac{-\Delta H\°_{vap}}{R} .(\frac{1}{T_{2}} -\frac{1}{T_{1}} )

where,

R is the ideal gas constant

ln(\frac{253torr}{35torr})=\frac{-\Delta H\°_{vap}}{8.314J/K.mol} .(\frac{1}{356.8K}-\frac{1}{385.10K})\\ \Delta H\°_{vap}=-79.8 \times 10^{4} J/mol

6 0
3 years ago
What number do you never write as a coefficient?
N76 [4]

Answer:

When no coefficient is written in front of a formula it is assumed to be 1. 4. Numbers appearing in the formulas are known as subscripts. These can never be changed when balancing the equation or you will change the identity of the substance.

Explanation:

1. Reactants go on the left hand side and products go on the right hand side of a chemical equation. Be sure to write the correct formulas for the reactants and products.

· Remember atoms are conserved in a chemical reaction. ie they are neither created or destroyed. So all the atoms in the reactants must end up somewhere among the products.

2. Count the number of atoms of each element, compound or ion in the reactants and products. If they are not equal proceed further.

3. Balance the atoms one at a time by placing coefficients in front of the formula so that the numbers of atoms of each element are equal on both sides of the equation. Remember atoms may exist in an element, compound or ion.

· It is usually easier to start with the atoms that occur in only one substance on each side of the equation.

· Balance the atoms that occur in compounds before attempting to balance atoms that occur in elemental form. e.g. H2, O2 or Cl2

· To make it easier if a polyatomic ion appears unchanged on both sides of the equation treat it as a whole unit.

· When no coefficient is written in front of a formula it is assumed to be 1.

4. Numbers appearing in the formulas are known as subscripts. These can never be changed when balancing the equation or you will change the identity of the substance.

· Remember with subscripts, any number to the right of parentheses multiplies each subscript within the parentheses.

eg Fe2(SO4)3 contains 2 Fe atoms, 3 S atoms and 12 O atoms.

5. Finally make sure that all the coefficients are in the smallest possible whole number ratio.

4 0
3 years ago
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