Answer:
Explanation:
By reading the statement, it is inferred that molarity must be computed. The amount of moles of hydrocloric acid is:
Finally, the molarity of the solution is:
Answer:
d= 14.007 amu
Explanation:
Abundance of N¹⁴ = 99.63%
Abundance of N¹⁵ = 0.37%
Atomic mass of N¹⁴ = 14.003 amu
Atomic mass of N¹⁵ = 15.000 amu
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100
Average atomic mass = 1395.12 + 5.55 / 100
Average atomic mass = 1400.67/ 100
Average atomic mass = 14.007 amu.
...because hydrogen bonds are formed between ammonia molecules.
(-_-(-_-)-_-)
Answer: is C=1650j because 45^0 evaluate the power. 1c the coefficient of 1 doesn't have to be written, so the answer particularly be C.
Explanation: I hope that helped !
