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g100num [7]
3 years ago
7

One hundred fifty joules of heat are removed from a heat reservoir at a temperature of 150 K. What is the entropy change of the

reservoir (in J/K)?
Chemistry
1 answer:
Sidana [21]3 years ago
3 0

Answer:

ΔS surrounding (entropy change of the reservoir) = -1 J/K

Explanation:

Given:

Change in heat (ΔH) = 150 joules

Temperature (T) = 150 K

Find:

ΔS surrounding (entropy change of the reservoir)

Computation:

ΔS surrounding (entropy change of the reservoir) = - ΔH / T

ΔS surrounding (entropy change of the reservoir) = - 150 / 150

ΔS surrounding (entropy change of the reservoir) = -1 J/K

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