3. Decomposition of a sample of KCIO3(s) produced 25.2 mL of 020, at a temperature of

Chemistry

1 answer:

dsp733 years ago

6 0

The volume of Oxygen gas=26.712 ml

<h3>Further explanation</h3>

The pressure constant = 89.6 kPa, so we use Charles's Law

<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature </em>

$\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

V₁=25.2 ml

T₁=27+273=300 K

T₂=45+273=318 K

$\tt V_2=\dfrac{V_1\times T_2}{T_1}\\\\V_2=\dfrac{25.2\times 318}{300}\\\\V_2=26.712~ml$

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