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3 years ago

An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?

2 answers:

6 0

The answer to ur question corresponds to the information u provided in option A.
please mark me brainiest on this and thank me

Svet_ta [14]3 years ago

5 0

Answer:

Option A: atomic number = 26, atomic mass = 56, net charge = 3+

Explanation:

Every atom has the same number of electrons as protons. This means that the atom is electrically neutral. If the atom gains or loses electrons that balance is lost ant the atom becomes an ion. For example an isolated iron atom has 26 protons into the nucleus. In order to be electrically neutral, 26 electrons must be moving in its orbitals.

If electrons are lost there will be an excess of protons over electrons, it means an ion with postive charge is formed. These kind of ions are called cations.

If electrons are gained there will be an excess of electrons over protons. In this case the ion formed is called an anion, which is an ion negatively charged.

On the other hand, atomic mass is defined as the sum of its number of protons and neutrons. The number of protons present in the atoms of a given element is always the same (all the iron atoms have 26 protons into the nucleus). However, the number of neutrons may vary in the iron atoms. Some of them have 30 neutrons. But there are other iron atoms having 28 or 31 neutrons. Atoms with the same atomic number but different numbers of neutrons are said to be isotopes.

In this current example the number of protons doesn't match with the number of electrons. It means that the atom is not electrically neutral and we have an iron cation. To know what the net charge is we substract the number of electrons (23) from the number of protons (26).

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2 years ago

The standard free energy of activation of one reaction A is 95.00 kJ mol–1 (22.71 kcal mol–1). The standard free energy of activ

diamong [38]

Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = $Ae^{\frac{-E_{a} }{RT} }$

Where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = $Ae^{\frac{-95000}{(8.314)(298)} }$

And for B the rate constant k₂ is given by k₂ = $Ae^{\frac{-74200 }{(8.314)(298)} }$

k₁ = A×2.225×10⁻¹⁷

k₂ = A×9.850×10⁻¹⁴

As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

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3 years ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

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Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

6 0

3 years ago

What is the age of mummified primate skin that contains 8.25% of the original quantity of 14C?

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Answer:

20619.4793 years

Explanation:

The half life of carbon-14 = 5730 years

The formula for the half life for a first order kinetic reaction is:

$t_{1/2}=\frac {ln\ 2}{k}$

Where,

$t_{1/2}$ is the half life

k is the rate constant.

Thus rate constant is:

5730 years=ln(2)/k

k = 1.21×10⁻⁴ years ⁻¹

Using integrated rate law as:

$ln\ \frac {A_t}{A_0}=-k\times t$

Where,

$A_t$ is the concentration at time t

$A_0$ is the initial concentration

Given that the final concentration contains 8.25 % of the original quantity which means that:

$\frac {A_t}{A_0}=0.0825$

So,

ln(.0825)= -1.21×10⁻⁴×t

t = 20619.4793 years

8 0

3 years ago