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3 years ago

How do Earth’s plates able to move?

Chemistry

2 answers:

KiRa [710]3 years ago

7 0

Answer/Explanation:

movement can be cause by the intense heat in the earth's core, which causes molten rock in the mantle layer to move. it moves in a pattern called 'convection cell' which can form when the warm material rises, then cools, and eventually sink down. then the process repeats (cooled, warms up and rises.. etc..)

I hope this was what you were kinda looking for:) - T

PS. HAVE A GOOD DAY! I LIKEYOUR PROFILE HAFHAS

Ann [662]3 years ago

6 0

Answer:

Plates at our planet's surface move because of the intense heat in the Earth's core

Explanation:

Hopefully this helps, I believe in you! ^^

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Consider the reaction Mg(s) + I2 (s) → MgI2 (s) Identify the limiting reagent in each of the reaction mixtures below:

Lapatulllka [165]

Answer:

a) Nor Mg, neither I2 is the limiting reactant.

b) I2 is the limiting reactant

c) Mg is the limiting reactant

d) Mg is the limiting reactant

e) Nor Mg, neither I2 is the limiting reactant.

f) I2 is the limiting reactant

g) Nor Mg, neither I2 is the limiting reactant.

h) I2 is the limiting reactant

i) Mg is the limiting reactant

Explanation:

Step 1: The balanced equation:

Mg(s) + I2(s) → MgI2(s)

For 1 mol of Mg we need 1 mol of I2 to produce 1 mol of MgI2

a. 100 atoms of Mg and 100 molecules of I2

We'll have the following equation:

100 Mg(s) + 100 I2(s) → 100MgI2(s)

This is a stoichiometric mixture. Nor Mg, neither I2 is the limiting reactant.

b. 150 atoms of Mg and 100 molecules of I2

We'll have the following equation:

150 Mg(s) + 100 I2(s) → 100 MgI2(s)

I2 is the limiting reactant, and will be completely consumed. There will be consumed 100 Mg atoms. There will remain 50 Mg atoms.

There will be produced 100 MgI2 molecules.

c. 200 atoms of Mg and 300 molecules of I2

We'll have the following equation:

200 Mg(s) + 300 I2(s) →200 MgI2(s)

Mg is the limiting reactant, and will be completely consumed. There will be consumed 200 I2 molecules. There will remain 100 I2 molecules.

There will be produced 200 MgI2 molecules.

d. 0.16 mol Mg and 0.25 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Mg is the limiting reactant, and will be completely consumed. There will be consumed 0.16 mol of I2. There will remain 0.09 mol of I2.

There will be produced 0.16 mol of MgI2.

e. 0.14 mol Mg and 0.14 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

This is a stoichiometric mixture. Nor Mg, neither I2 is the limiting reactant.

There will be consumed 0.14 mol of Mg and 0.14 mol of I2. there will be produced 0.14 mol of MgI2

f. 0.12 mol Mg and 0.08 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

I2 is the limiting reactant, and will be completely consumed. There will be consumed 0.08 moles of Mg. There will remain 0.04 moles of Mg.

There will be produced 0.08 moles of MgI2.

g. 6.078 g Mg and 63.455 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 6.078 grams / 24.31 g/mol = 0.250 moles

Number of moles I2 = 63.455 grams/ 253.8 g/mol = 0.250 moles

This is a stoichiometric mixture. Nor Mg, neither I2 is the limiting reactant.

There will be consumed 0.250 mol of Mg and 0.250 mol of I2. there will be produced 0.250 mol of MgI2

h. 1.00 g Mg and 2.00 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 1.00 grams / 24.31 g/mol = 0.0411 moles

Number of moles I2 = 2.00 grams/ 253.8 g/mol = 0.00788 moles

I2 is the limiting reactant, and will be completely consumed. There will be consumed 0.00788 moles of Mg. There will remain 0.03322 moles of Mg.

There will be produced 0.00788 moles of MgI2.

i. 1.00 g Mg and 2.00 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 1.00 grams / 24.31 g/mol = 0.0411 moles

Number of moles I2 = 20.00 grams/ 253.8 g/mol = 0.0788 moles

Mg is the limiting reactant, and will be completely consumed. There will be consumed 0.0411 moles of Mg. There will remain 0.0377 moles of I2.

There will be produced 0.0411 moles of MgI2.

4 0

3 years ago

All elements are pure substances. True False

oee [108]

It can be a compound or a single element. An element is a pure substance that cannot be separated into simpler substances by chemical or physical means. There are about 117 elements, but carbon, hydrogen, nitrogen and oxygen are only a few that make up the largest portion of Earth.
hopefully that helps

5 0

3 years ago

Iron forms rust, expressed as Fe2O3.

Elina [12.6K]

Answer:

it's C. 159.70 g

Explanation:

hopefully that helps

3 0

3 years ago

Help me please) attached the screen below. Thanks

Vitek1552 [10]

Answer:

1) d = 2.4 g/cm³

2) m = 25 g

3) v = 126.7 cm³

Explanation:

Given data:

Mass of material = 24 g

Volume of material = 10 cm³

Density of material = ?

Solution:

Formula:

d = m/v

by putting value,

d = 24 g / 10 cm³

d = 2.4 g/cm³

2) Given data:

Density of material = 5 g/cm³

Volume of material = 5 cm³

Mass of material = ?

Solution:

Formula:

d = m/v

5 g/cm³ = m / 5 cm³

m = 5 g/cm³×5 cm³

m = 25 g

3)Given data:

Density of material = 3 g/cm³

Mass of material = 380 g

Volume of material = ?

Solution:

Formula:

d = m/v

3 g/cm³ = 380 g / v

v = 380 g /3 g/cm³

v = 126.7 cm³

7 0

3 years ago

Can someone's help me with this

labwork [276]

Oh ok just wait a minute

7 0

4 years ago