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podryga [215]
1 year ago
11

Write the slope intercept form of the equation given the point (-2,4) and a slope of 3

Mathematics
1 answer:
Hitman42 [59]1 year ago
7 0

Given the points:

(x, y) ==> (-2, 4)

slope, m = 3

To write the slope intercept form, use the form below:

y = mx + b

Where m = slope and b = y-intercept.

Now, substitute -2 for x, 4 for y, and m for 3 in the equation above to solve for b.

We have:

y = mx + b

4 = 3(-2) + b

4 = -6 + b

Add 6 to both sides:

4 + 6 = -6 + 6 + b

10 = b

b = 10

Therefore, the slope intercept form of the equation is:

y = 3x + 10

ANSWER:

y = 3x + 10

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Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

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