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Gnoma [55]
3 years ago
10

What is the correct answer? Please hurry

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0

Answer:

2.5m

Step-by-step explanation:

5/2 = 2.5

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What is the answer a or b to this question
galina1969 [7]
The answer would be A.

Explanation:

If they enter with one car, that’s a price of $3 for the car alone. Because there’s also a fee for each person who enters, and there is a family of 5 who enters, x is representative of the cost for each person who enters. Therefore, there would be 5 x’s and one 3 that when solved would add up to the total of $45 they spent. That would mean A is correct because the equation would be x + x + x + x + x + 3 = 45.
5 0
2 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
-8+5w^4=28 what is w=
Murljashka [212]

Answer:

w = ±\sqrt[4]{36/5}

Step-by-step explanation:

-8+5w^4=28

You can regroup it:

5w^4 - 8 = 28

Add 8 to both side:

5w^4 = 28 + 8

5w^4 = 36

Divide both side by 5:

5w^4/5 = 36/5

w^4 = 36/5

Take the 4 root of both sides:

w = ±\sqrt[4]{36/5}

Hope this help you :3

3 0
3 years ago
Read 2 more answers
How do you divide <br> 2 / 7367
Helen [10]

Answer:

0.00027148092

Step-by-step explanation:

calculator lol

4 0
4 years ago
Read 2 more answers
Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil
KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

   =  6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

   =  9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

   = 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

   =  4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

   =  4.5 days to get to the next pond.

3 0
3 years ago
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