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3 years ago

PLZ HELP

Mathematics

1 answer:

Xelga [282]3 years ago

8 0

Answer:

$21 \times < 3 - 63 \times < 2 + 15 \times - 45$

$a.21 \times < 2( \times - 3$

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There are 20 beads in a bag, of which 8 beads are white, 2 beads are yellow, 6 beads are green, and the rest are blue. Janina wi

USPshnik [31]

Answer:

8/20 in simplest form this would be 2/5

Step-by-step explanation:

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3 years ago

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WILL MARK! please help:) Find x and y so that ABCD will be a parallelogram.

Volgvan

Answer:

The answer is the first one; x = 6 y =42

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3 years ago

Circle any equivalent ratios from the list below.

marysya [2.9K]

Answer:

Equivalent ratios: we can that the first ratio is equivalent to the second, then third ratio is equivalent to the forth.

Ratio: 1: 2 Value of the Ratio: 1/2

Ratio: 5: 10 Value of the Ratio: 1/2

Ratio: 6: 16 Value of the Ratio: 3/8

Ratio: 12: 32 Value of the Ratio: 3/8

We notice that if the values are equivalent the ratios are equivalent

Step-by-step explanation:

Equivalent ratios:

To get if ratios are equivalent we look for the constant between ratios

a.Ratio: 1: 2 and Ratio: 5: 10

We apply the method of comparing the first term of both ratios , and the second term of both ratios. We see the constant is 5 ( 1/5 is equal to 2/10)

We do the same with third and forth ratio

Ratio: 6: 16 compare to Ratio: 12: 32

6/12 is equal to 16/32 the constant is 2

So, we can that the first ratio is equivalent to the second, then, third ratio is equivalent to the forth.

Value of the Ratio: The value is a ratio written as a fraction.

Ratio: 1: 2 Value of the Ratio: 1/2

Ratio: 5: 10 Value of the Ratio: 5/10 if we divide both sides by 5, we can say Value of the Ratio: 1/2

Ratio: 6: 16 Value of the Ratio: 6/16 if we divide both sides by 2, we can say the value is 3/ 8

Ratio: 12: 32 Value of the Ratio: 12/32 if we divide both sides by 4, we can say the value is 3/ 8

If the values are equivalent the ratios are equivalent.

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3 years ago

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Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

$(x,y)\to (y,-x)$

Using this rule, we get

$A(-3,6)\to A'(6,3)$

$B(2,9)\to B'(9,-2)$

$C(1,1)\to C'(1,-1)$

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

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4 years ago

You might need: CalculatorThe angle O, is located in Quadrant III, and sin((.)1213What is the value of cos((,)?Express your answ

Wewaii [24]

We know that:

$\sin (\theta_1)=-\frac{12}{13}$

There is also an interesting property that relates the sine and the cosine of an angle:

$\sin ^2(\theta_1)+\cos ^2(\theta_1)=1$

We can find the cosine of theta using this equation:

$\begin{gathered} \cos ^2(\theta_1)=1-\sin ^2(\theta_1) \\ \cos (\theta_1)=\sqrt{1-\sin^2(\theta_1)} \\ \cos (\theta_1)=\sqrt[]{1-(-\frac{12}{13})^2} \\ \lvert\cos (\theta_1)\rvert=\sqrt[]{1-\frac{144}{169}}=\sqrt[]{\frac{25}{169}} \\ \lvert\cos (\theta_1)\rvert=\frac{5}{13} \end{gathered}$

Since theta is in the third quadrant then its cosine must be a negative number so:

$\cos (\theta_1)=-\frac{5}{13}$

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1 year ago