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s344n2d4d5 [400]

2 years ago

11

A jewelry box is in the shape of a rectangular with a volume of 528 cubic inches l. The length of the box is 12 inches and the h

eight is 5 1/2 inches. What is the width of the jewelry box

1 answer:

Artist 52 [7]2 years ago

5 0

Volume=length*height*width
528=12*5.5*w

divide both sides by 12
44=5.5w
divide both sides by 5.5
8=w
width is 8 inches

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A chocolate chip cookie recipe asks for three and one half times as much flour as chocolate chips. If one and three quarters cup

Ganezh [65]

3.5 times as much flour as chocolate chips....
f = 3.5c
f = 1 3/4 (or 1.75)

1.75 = 3.5c
1.75 / 3.5 = c
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6 0

2 years ago

Two collinear points on a line are given in the table below:

katrin [286]

Answer:

$(4,3)$ and $(7,2)$ do not lie on the line

Step-by-step explanation:

Given

$(0,0)\ and\ (2,1)$

Required

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First, we need to determine the slope (m) of the line:

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Next, we determine the line equation using:

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Where

$m = \frac{1}{2}$

$(x_1,y_1) = (0,0)$

$y - y_1 = m(x -x_1)$ becomes

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To determine which point is on the line, we simply plug in the values of x to in the equation check.

For $(4,2)$

$x = 4$ and $y =2$

Substitute 4 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 4$

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$x = 4$ and $y = 3$

Substitute 4 for x and 3 for y in $y = \frac{1}{2}x$

$3 = \frac{1}{2} * 4$

$3 = \frac{4}{2}$

$3 \neq 2$

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For $(7,2)$

$x = 7$ and $y = 2$

Substitute 7 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 7$

$2 = \frac{7}{2}$

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<em></em>

<em>This point is not on the graph</em>

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<em></em> $(\frac{4}{8},\frac{2}{8})$ <em></em>

<em></em> $x = \frac{4}{8}$ and<em> </em> $y = \frac{2}{8}$ <em></em>

<em>Substitute </em> $\frac{4}{8}$ <em> for x and </em> $\frac{2}{8}$ <em> for y in </em> $y = \frac{1}{2}x$ <em></em>

<em></em> $\frac{2}{8} = \frac{1}{2} * \frac{4}{8}$ <em></em>

<em></em> $\frac{2}{8} = \frac{1 * 4}{8 * 2}$ <em></em>

<em></em> $\frac{2}{8} = \frac{4}{16}$ <em></em>

<em></em> $\frac{1}{4} = \frac{1}{4}$ <em></em>

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mojhsa [17]

Answer:

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** From what the problem said, we know that we selected the correct equation.

I am joyous to assist you anytime.

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Answer:

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Step-by-step explanation:

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3 years ago