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cricket20 [7]
3 years ago
8

Which statement explains how you could use coordinate geometry to prove that quadrilateral ABCD is a parallelogram? Shape ABCD i

s shown. Point A is at negative 3, 5. Point B is at 2, 6. Point C is at 0, 2. Point D is at negative 5, 1.
Mathematics
1 answer:
inysia [295]3 years ago
3 0

the answer is 3,5 because the estement of the ther is no negative

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How do you solve this help​
vfiekz [6]

Answer:

arc PST = 254°

Step-by-step explanation:

arc QPT = 180° because it is a diameter

arc PQ = 74°

arc PT = 180° - 74° = 106°

arc PST = 360° - 106° = 254°

5 0
3 years ago
Nick and Tasha are buying supplies for a camping trip. They need to buy chocolate bars to make s’mores, their favorite campfire
Harlamova29_29 [7]

Answer:

9/10

Step-by-step explanation:

first you find the lowest common denominator. 1/2 becomes 5/10, 2/5 becomes 4/10. 5/10+4/10=9/10

7 0
3 years ago
Between which two ordered pairs does the graph of f(x) = one-halfx2 + x – 9 cross the negative x-axis?
Anit [1.1K]

Answer:

Step-by-step explanation:

we have that

f(x) = x^2 + x - 9

Using a graph tool

see the attached figure

The function represent a vertical parabola that open up

the vertex is a minimum-------> is the point (-0.5, -9.3)

The x-intercepts are the points when the y coordinate is equal to zero

The x-intercepts are the points (-3.5, 0)  and (2.5, 0)

so

the function cross the negative x-axis at point

therefore, the answer is

(-4, 0) and (-3, 0)

6 0
3 years ago
Read 2 more answers
ILL GIVE U BRANLIEST
Lady bird [3.3K]

Answer:

1. 0.6p

Step-by-step explanation: Well its quite obvious since its 40%

7 0
2 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
3 years ago
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