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3 years ago

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Nick and Tasha are buying supplies for a camping trip. They need to buy chocolate bars to make s’mores, their favorite campfire

dessert. Each of them has a different recipe for their perfect s’mores
Nick likes to use 12 of Chocolate bar to make a s’more. Tasha will only eat a s’more that’s is made 25 of a chocolate bar. What fraction of chocolate will nick and Tasha use in total if they each eat one s’more?

1 answer:

Harlamova29_29 [7]3 years ago

7 0

Answer:

9/10

Step-by-step explanation:

first you find the lowest common denominator. 1/2 becomes 5/10, 2/5 becomes 4/10. 5/10+4/10=9/10

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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas

saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by $s(t) = -t^3+3t^2+7t +4$ , where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

$s(t) = -t^3+3t^2+7t +4$

Derivate w.r.t. time,

$v(t)=s'(t) = -3t^2+6t+7$

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

$x=-\frac{b}{2a}$

Where, a=-3, b=6 and c=7

$t=-\frac{6}{2(-3)}$

$t=-\frac{6}{-6}$

$t=1$

As 1 lie between interval [0,4]

Substitute t=1 in the function,

$v(t)= -3(1)^2+6(1)+7$

$v(t)= -3+6+7$

$v(1)=10$

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0

3 years ago

Read 2 more answers

Find the sum: 35,076 + 6,825 = ______.

Tcecarenko [31]

41,901

that’s the answer

5 0

2 years ago

Read 2 more answers

1 liter is equivalent to 1,000 milliliters how many litters are in 2,500 milliliters.

Furkat [3]

You can create and solve a proportion to get this answer.
Let x be the number of litters in 2500.

1. Write out proportion. 1/1000=x/2500
2. Cross Multiply. 1000x=2500
3. Divide by 1000 on each side. x=25

3 0

3 years ago

Molly drew a blue line that was 19 1/12 inches long. Then she drew a green line that was

antoniya [11.8K]

Answer:

10 2/3 in

Step-by-step explanation:

<u>Subtract the values:</u>

19 1/12 - 8 5/12 =
18 13/12 - 8 5/12 =
18 - 8 + 13/12 - 5/12 =
10 + 8/12 =
10 8/12 =
10 2/3 in

6 0

3 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

(C) Tan(A + B) = $\frac{Sin(A +B)}{Cos(A + B)}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago