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3 years ago

DESCRIBE the five types of chemical reactions

2 answers:

4 0

Syntesis- is a reaction that occur when two different atoms interact to form a different compound.
Decomposition- is a reaction in which compound breaks down into two or more simple substances.
Single displacement- is a reaction in which one element is substituted for another element in a compound
Double displacement- is a reaction in which the reactant ions exchange places to form new products.
Combustion- is a reaction in which the substance reacts with oxygen from the air, simply said combustion is when something’s burininv.

m_a_m_a [10]3 years ago

4 0

Answer:

<h3>Combustion Reactions</h3>

A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.

<h3>Decomposition Reactions</h3>

A decomposition reaction is a reaction in which a compound breaks down into two or more simpler substances.

<h3>Single-Replacement Reactions</h3>

A single-replacement reaction is a reaction in which one element replaces a similar element in a compound.

<h3>Double-Replacement Reactions</h3>

A double-replacement reaction is a reaction in which the positive and negative ions of two ionic compounds exchange places to form two new compounds.

<h3>Combination Reactions</h3>

A combination reaction, also known as a synthesis reaction, is a reaction in which two or more substances combine to form a single new substance.

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Given the value of the equilibrium constant (Kc) for the equation (a), calculate the equilibrium constant for equation (b)

matrenka [14]

Answer: The value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

Explanation:

The given chemical equation follows:

$O_2(g)\rightarrow \frac{2}{3}O_3(g)+\frac{1}{2}O_2(g)$

The equilibrium constant for the above equation is $5.77\times 10^{-9}$

We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:

$3O_2(g)\rightarrow 2O_3(g)$

The equilibrium constant for this reaction will be the cube of the initial reaction.

If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{eq}'=(5.77\times 10^{-9})^3=1.92\times 10^{-25}$

Hence, the value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

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3 years ago

Different enzymes that catalyze the same reaction are known as _____.

maw [93]

Answer:

<em><u>Isozymes</u></em>

Explanation:

Isozymes are enzymes that differ in amino acid sequence but catalyze the same chemical reaction. These enzymes usually display different kinetic parameters, or different regulatory properties.

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