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Step2247 [10]
3 years ago
6

In this chemical formula: 3NH4 (ammonium) This chemical formula means there are 3 _____________ ___________, and 4 __________ __

______ in each molecule.
Chemistry
1 answer:
seropon [69]3 years ago
5 0

Answer:

hope it helped you

Explanation:

3 atoms of nitrogen and 4 atoms of hydrogen in each molecule

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scZoUnD [109]

The answer is B
Vaporization
6 0
3 years ago
Please help!!!!! I need the correct answer quickly!!!
xxMikexx [17]

Answer :

The oxidation state of oxygen (O) in OF_2  is, (+2)

The oxidation state of carbon (C) in CO  is, (+2)

The oxidation state of nitrogen (N) in K_3N  is, (-3)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

(a) The given compound is, OF_2

Let the oxidation state of 'O' be, 'x'

x+2(-1)=0\\\\x-2=0\\\\x=+2

The oxidation state of oxygen (O) in OF_2  is, (+2)

(b) The given compound is, CO

Let the oxidation state of 'C' be, 'x'

x+(-2)=0\\\\x-2=0\\\\x=+2

The oxidation state of carbon (C) in CO  is, (+2)

(c) The given compound is, K_3N

Let the oxidation state of 'N' be, 'x'

3(+1)+x=0\\\\3+x=0\\\\x=-3

The oxidation state of nitrogen (N) in K_3N  is, (-3)

7 0
3 years ago
Read 2 more answers
At elevated temperatures, methylisonitrile (CH3NC) converts to acetonitrile (CH3CN): CH3NC(g) --> CH3CN(g) At the start of th
pshichka [43]

Answer:

A. 3.7 x 10⁻³

Explanation:

In the beginning of the reaction there are 0.200 moles of reactant. After 25 minutes, remain 0.108 moles. That means the moles that wer descomposed are:

0.200 moles - 0.108 moles = 0.092 moles of reactant were descomposed.

That descomposition occurs in 25 minutes. The average rate of descomposition in moles / minute are:

0.092 moles Methyl isonitrile / 25 minutes = 3.7x10⁻³ mol/min.

Right option is:

<h3>A. 3.7 x 10⁻³</h3>
7 0
4 years ago
What are the units for the atomic radius?
Musya8 [376]
Angstroms 1.0 x 10^-10 meters, nanometer 1.0 x 10^-9 meters, and picometer 1.0 x 10^-12 meters.
8 0
3 years ago
If kb for nx3 is 4.0×10−6, what is the poh of a 0.175 m aqueous solution of nx3?
Elena-2011 [213]
<h3><u>Answer;</u></h3>

pOH = 3.08

<h3><u>Explanation;</u></h3>

NX3 + H2O <----> NHX3+ + OH-  

Kb = 4.0 x 10^-6

Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).

c(NH₄⁺) = c(OH⁻) = x.

x² = Kb · c(NH₃)

x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = c(OH⁻) = √(7.0 × 10⁻⁷)

    = 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

        =- log ( 8.367 × 10⁻⁴)

        <u>= 3.08</u>

7 0
3 years ago
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