Question

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Suppose that 1.19 × 103 kg of Fe is obtained from a 1.90 × 103 kg sample of Fe2O3. Assuming that the reaction goes to completion, what is the percent purity of Fe2O3 in the original sample?

Answer 1

Answer:

$89.55~\%~of~Fe_2O_3~in~the~sample$

Explanation:

The first step in this reaction is the converstion from Kg of $Fe$ to  grams of $Fe_2O_3$.

$1.19x10^3~Kg~Fe~\frac{1000g~Fe}{1~Kg~Fe}~\frac{1~mol~Fe}{55.84~g~Fe}~\frac{1~mol~Fe_2O_3}{2~mol~Fe}~\frac{159.68~g~Fe_2O_3}{1~mol~Fe_2O_3}~\frac{1~Kg~Fe_2O_3}{1000~g~Fe_2O_3}$

$X~=~1.7x10^3~Kg~Fe_2O_3$

Then we can calculate the percentage of  $Fe_2O_3$ in the sample:

$\%~Fe_2O_3~=~\frac{1.7x10^3~Kg~Fe_2O_3}{1.9x10^3~Kg~Sample}*100$

$89.55~\%~of~Fe_2O_3~in~the~sample$