Id just like the awnser please.

the x and y axis are tangent to a circle with radius 3 units. write a standard equation of the circle.

Mekhanik [1.2K]

Given:

The x and y axis are tangent to a circle with radius 3 units.

To find:

The standard form of the circle.

Solution:

It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.

We know that the radius of the circle are perpendicular to the tangent at the point of tangency.

It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Putting $h=3,k=3,r=3$ , we get

$(x-3)^2+(y-3)^2=3^2$

$(x-3)^2+(y-3)^2=9$

Therefore, the standard form of the given circle is $(x-3)^2+(y-3)^2=9$ .

3 0

2 years ago

the Golden Ratio, is present not just in mathematics, but may also be present within your own brain and body (at the atomic or s

Anton [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Extraordinary claims require extraordinary evidence. You have no evidence here what so ever. IF you have some, please do share.

<span>Otherwise, please try to keep questions about religious and spiritual and paranormal stuff out of the Science and Math category.</span>

8 0

3 years ago

Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$