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3 years ago

Factor 2w+6

Mathematics

1 answer:

natta225 [31]3 years ago

6 0

Answer:

2( w + 3 )

Step-by-step explanation:

Well first off, since theres no common term to factor out, I had to split 6 in half

so 2 w + 6 becomes 2w + 2 x 3.

I then factored out 2 because it's a common term,

which then leaves: 2( w + 3 )

basically, you have to find a common term to factor out, if you don't see one, you have to do something to a number so there's common terms.

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I need the answer!!!

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Answer:

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Step-by-step explanation:

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Answer:

The correct answer is:

(1) d

(2) b

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Step-by-step explanation:

The given problem is incomplete. Find the attachment of the full question.

According to the question,

(1)

By putting x = -2, we get

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(2)

By putting x = 0, we get

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(3)

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Marizza181 [45]

After solving $\sqrt[5]{128x^8y^2}$ we get $2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}$

Step-by-step explanation:

We need to solve $\sqrt[5]{128x^8y^2}$

Applying the rule: $\sqrt[a]{xy}=\sqrt[a]{x}.\sqrt[a]{y}$

$\sqrt[5]{128x^8y^2}\\=\sqrt[5]{128}\sqrt[5]{x^8}\sqrt[5]{y^2}\\We\,\,know\,\,that\,\,128=2\times2\times2\times2\times2\times2\times2=2^7\,\,or\,\,2^5.2^2\\=\sqrt[5]{2^5.2^2}\sqrt[5]{x^5.x^3}\sqrt[5]{y^2}\\=(2^5)^{\frac{1}{5}}\sqrt[5]{2^2}\sqrt[5]{x^5}\sqrt[5]{x^3}\sqrt[5]{y^2}\\=2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}$

So, After solving $\sqrt[5]{128x^8y^2}$ we get $2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}$

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

#learnwithBrainly

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