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3 years ago

2. Ken combined a triangle and a trapezoid to

Mathematics

1 answer:

jarptica [38.1K]3 years ago

8 0

Answer:

Step-by-step explanation:

area of a triangle = 12 in²

area of a trapezoid = 24 in²

just combine the two shape (see image)

then add the area.

total area = 12 + 24

= 36 in²

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Answer:

16 cm

Step-by-step explanation:

A right triangle, with the hypotenuse = 18, one side = 7, and the other side = x.

Since this is a right triangle, use the pythagorean theorem to find the value for x.

let a = 7 for one side, and let c = 18 for the hypotenuse. And, let c = x for the other side.

The pythagorean theorem is: c^2 = a^2 + b^2.

18^2 = 7^2 + x^2324 = 49 +x^2

x^2 = 324 - 49 = 275So, x = sqrt(275) = 16.5 cm

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2 years ago

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Suppose triangle ABC will be dilated using the rule . What will be the distance from the center of dilation, Q, to the image of

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Answer:

Step-by-step explanation:

The rule of dilation is $D_{Q,\frac{2}{3}}.$ This means that each distance QX' is equal to $\dfrac{2}{3}QX,$ where X is initial point and X' is its image after dilation.

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3 years ago

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What is x 3x-11+9=10

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Answer: x = 4

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3 years ago

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Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

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