9514 1404 393
Answer:
Step-by-step explanation:
The ratios all have ...
first number : second number = 1 : 4
Using first numbers of 1, 2, 3, the second numbers can be found by multiplying these by 4. (1, 4), (2, 8), (3, 12)
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You plot these (x, y) points the same way you plot <em>any</em> point on a coordinate grid. The first (x) value is the horizontal distance from the vertical axis. Positive is to the right. The second (y) value is the vertical distance from the horizontal axis. Positive is up.
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Of course, the origin is where the horizontal and vertical axes meet. It can be convenient to find one of the coordinates on its respective axis, then use the other coordinate to find the point at the desired distance from that axis.
Usually, you would choose the axis on the basis of how easy it is to determine exactly where the coordinate lies. If the y-axis is marked every 5, for example, it might be hard to determine where a multiple of 4 will lie. Locating the x-coordinate on the x-axis may be an easier way to start.
You would use the point-slope equation of y-y₁=mx(x-x₁)
So the rate of change is the slope and equals m, so m=-4
and has a solution at (-5,2) which would be the (x₁, y₁) and then it is just plugging in the numbers
y - (2) = (-4)(x - (-5))
y - 2 = -4 (x+5)
y - 2 = -4x - 20
y = -4x - 18
Answer:
y= (C -Ax)/B
x= (C -By)/A
Step-by-step explanation:
Ax+ By = C
solve for y
Subtract AX from each side
Ax+ By - Ax = C-Ax
By = C -Ax
Divide by B
By /B= (C -Ax)/B
y= (C -Ax)/B
solve for x
Subtract By from each side
Ax+ By - By = C-By
Ax = C -By
Divide by A
Ax/A= (C -By)/A
x= (C -By)/A
The area of Erin's circle to the nearest hundredth is 50.24 in².
<h3>What is the area of the circle?
</h3>
A circle is a bounded figure which points from its center to its circumference is equidistant.
Area of a circle = πr²
Where :
3.14 X 4²
(3.14) (4) (4) = 50.24 in²
To learn more about the area of a circle, please check: brainly.com/question/14351152
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Answer:
Step-by-step explanation:
math is a thing pls like this it was meaningful ;;;;;;;;;0