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den301095 [7]
3 years ago
11

How do you make a fraction that’s greater than one or just a fraction into a mixed number?

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

You multiply the denominator and the whole number then add the numerator.

Step-by-step explanation:

Example: 3\frac{2}{4}

You multiply 3 and 4

3*4=12

Then add the numerator

12+2=14

The final answer would be

\frac{14}{4}

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Please Help I Don't Understand!
asambeis [7]

Answer:

5.3

Step-by-step explanation:

Since they are similar triangles, we assume the ratio between AM/AN is equal to the ratio between MB/NC.
AM/AN = 6/8 = 3/4
If MB is 4
3/4 = MB/NC = 4/NC
3/4 = 4/NC

3NC = 16
NC = 16/3
16/3 = 5.333333

8 0
2 years ago
Solve P = 8/3 R + 30 for R.
vampirchik [111]

Answer:

R = (3P-30)/8

Step-by-step explanation:

subtract 30 from each side to get:

P-30 = \frac{8}{3}R

multiply each side by \frac{3}{8} to get:

\frac{3}{8} · P - 30 = R

R = (3P-30)/8

7 0
3 years ago
What is the inverse of the given relation y = 7x² ?
beks73 [17]

Answer:

y = square root(x/7)

Step-by-step explanation:

switch x and y

x = 7y^2

solve for y

x/7 = y^2

square root(x/7) =y

y inverse is

y= square root(x/7)

7 0
3 years ago
HELP PLEASE BE QUICK
rewona [7]

Answer:

Radius is 2 centimeters

Step-by-step explanation:

<u>4π is the area of a circle</u>

<u>Area of a circle = πr^2</u>

4π / π = πr^2 / π

sqrt(4) = sqrt(r^2)

2 = r

Answer:  Radius is 2 centimeters

4 0
3 years ago
Help me please asap :(
GREYUIT [131]
This is a fairly tedious problem. The only way to solve that I see is to simply list out all the possible cases and go through each one by one. You'll use the triangle inequality theorem to see if the triangles can be formed. The theorem says that a+b > c must be true for all sets of pairs. In other words, take any two sides and add them up. The sum must be greater than the third side. 

Going through all the combos possible (that I could find), this is what I got
Blue9,Green7,Orange4
Blue9,Green7,Purple12
Blue9,Green7,Red3
Blue9,Green7,Yellow5
Blue9,Orange4,Purple12
Blue9,Purple12,Yellow5
Green7,Orange4,Yellow5
Green7,Red3,Yellow5
Orange4,Red3,Yellow5

In all, I count 9 cases. So the answer to problem 1 is 9.

-----------------------------------------------------------

For problem 2, the best way may be to pick two segments at a time instead of one. However, I have a feeling that will take just as long as the first method. I haven't tried it out. Even though going through the rods one at a time takes a while, it's probably the best option so you don't overlook any cases. 


6 0
4 years ago
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