1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nady [450]
3 years ago
7

The college team won 30 games last year. This year it won 25 games what was the percent decrease of games won?

Mathematics
1 answer:
babymother [125]3 years ago
3 0
Since it decreased by 5 do 5 divided by 30 and you get the answer to be 16%
You might be interested in
PART A: A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the tr
Greeley [361]

Complete Question:

Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.

(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.  

(b) Determine the scale factor from the first map to the second map.

(c)  A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the triangle landmark on the second map?  

(d) Draw one of the triangles from part C. Label the side lengths and vertices accordingly. You may use this drawing tool or draw your triangle on paper:

Answer:

(a) Length = 4cm

(b) Scale factor = 0.5

(c) 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

Step-by-step explanation:

(a) Choose a length between 5 cm and 15 cm

Length =4cm <em>--- This is solely up to you (you can make use of any length between 5 cm and 15 cm)</em>

(b) The scale factor

The scale factor (k) is calculated as:

k = \frac{New\ Length}{Old\ Length}

k = \frac{4cm}{8cm}\\

k = 0.5

(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark

Using:

k = \frac{New\ Length}{Old\ Length}

The old lengths, in this case are: 3cm, 4cm and 5cm

Make New length the subject

New\ Length = k * Old\ Length

When Length = 3cm

New\ Length = 0.5 * 3cm = 1.5cm

When Length = 4cm

New\ Length = 0.5 * 4cm = 2cm

When Length = 5cm

New\ Length = 0.5 * 5cm = 2.5cm

So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

7 0
3 years ago
There was a 6 square foot piece of wrapping paper for a birthday present
TiliK225 [7]

where's the rest of question so I can help?

5 0
3 years ago
Read 2 more answers
How do you write 6,007,200 in words
kirill [66]
Six million, seven thousand two hundred
3 0
3 years ago
Read 2 more answers
the distance a jet travels varies directly as the number of hours it flies. A jet traveled 2875 miles in 5 hours. What is the co
skelet666 [1.2K]

Answer:

k = 575

Step-by-step explanation:

let d be distance and h time.

Given d varies directly as h then the equation relating them is

d = kh ← k is the constant of variation

To find k use the condition d = 2875, h = 5, then

2875 = 5k ( divide both sides by 5 )

k = 575

3 0
4 years ago
Triangle A’ B’ C’ is the image of triangle A B C under a rotation about the origin, (0,0)
S_A_V [24]

Answer:

The triangle A B C will be the image of triangle of A B C in origin (0,0)

8 0
3 years ago
Other questions:
  • What determines if an equation is a one-to-one function?​
    15·1 answer
  • Select correct equation rule​
    5·1 answer
  • ???????????????????????????
    12·1 answer
  • Which of the following side lengths are the legs? 6, 14, and 12
    9·2 answers
  • Is number 7 correct ? Please help
    12·1 answer
  • 6 1/3 + 3 1/4 +2 1/2=​
    5·2 answers
  • I Need Help Please I'm Out Of Time. :(
    12·2 answers
  • Does anyone know the answers to B and C
    9·1 answer
  • Can you plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz help me plz
    5·2 answers
  • A parallelogram when one side and two diagonals are given​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!