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3 years ago

The first person to answer this will get brainliest so good luck :D

Mathematics

2 answers:

nasty-shy [4]3 years ago

8 0

Answer:

In a covalent bond, electrons are ________________.

Choose one answer.

a. Shared

b. Transferred

c. Free

Step-by-step explanation:

Licemer1 [7]3 years ago

3 0

Answer:

lol

Step-by-step explanation:

I'm the first person!

LOL it's been so long since nobody answered this question lol

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The equation below describes a proportional relationship between x and y. What is the constant of proportionality? Y=4/7x

FromTheMoon [43]

Answer:

the given equation is y=4/7x

reciprocating both sides you get y/x =7/4

now x and y are directly porportional to each other so

x=ky where k is the constant

or x/y=k ......................(2)

equating 1 and 2

k=7/4

Step-by-step explanation:

4 0

3 years ago

What is the difference?

Musya8 [376]

Answer:

Are these the option or what what this suppose to be ??????

8 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

Write the equation for the area (A) in terms of width (w) of a playground if the length (l) is twice as long as the width (w)

Crazy boy [7]

It will be a system of equations.

A=1*w
l=2w

Solve by substitution.

5 0

4 years ago

"A passenger train traveled 100 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the fre

Pavel [41]

Answer: the rate of the passenger train is 100 mph.

Step-by-step explanation:

Let x represent the rate of the passenger train.

The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. It means that the rate of the freight train is (x - 10) mph

The passenger train traveled 100 miles. It means that the time it took travel 100 miles is

100/x

In the same amount of time, it took a freight train to travel 90 miles. It means that the time it took travel 90 miles is

90/(x - 10)

Since the time is the same, then

100/x = 90/(x - 10)

Cross multiplying, it becomes

100(x - 10) = 90x

100x - 1000 = 90x

100x - 90x = 1000

10x = 1000

x = 100 mph

7 0

4 years ago