He collected $264.00, $72.00 went to his homeroom, and $192.00 to the school
This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.
Answer:
I think 3
Step-by-step explanation:
i think 3
for real this time
Answer:
The statement written as a formula is. a12a9=125. We can simplify the fraction, and we have. a3=125. To solve for a , take the third root
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Here is how to start....you didn't include the equations in question, so I do not know what the answer may be
solve for x
y-10 = 5 x^2 divide thru by 5
(y-10)/5 = x^2 'sqrt' both sides
± sqrt( (y-10) / 5 = x change x's and y's
± sqrt ((x-10)/5) = y
