Answer:
Step-by-step explanation:
use formula
x^3+y^3=(x+y)^3-3*x*y(x+y)
=12^3-3*27(12)
=1728-972
=756
Answer:
the x-intercepts are (5, 0) and (-3, 0).
Step-by-step explanation:
The standard equation of a vertical parabola with vertex at (h, k) is
y = a(x - h)^2 + k.
Here we are told that the vertex is at (1, -16), which means that h = 1 and y = -16. Thus, we have:
y = a(x - 1)^2 + (-16).
We are told also that the graph passes through (0, -15). Substituting -15 for y and 0 for x, we get:
-15 = a(0 - 1)^2 - 16, or
-15 = a - 16
Then a must be 1, and the equation of the parabola is
y = (x - 1)^2 - 16.
Now to find the x-intercepts: Set y = 0 and solve for x:
0 = (x - 1)^2 - 16, or
(x - 1)^2 = 16, or
x - 1 = ±√16 = ±4
Then x = 1 ± 4, or x = 5 or x = -3, so the x-intercepts are (5, 0) and (-3, 0).
Answer:
<em>Point </em><em>B </em><em>represents </em><em>the </em><em>location </em><em>of </em>
<em>
</em>
Step-by-step explanation:
<em>As </em><em>the </em><em>value </em><em>of </em><em>under </em><em>root </em><em>1</em><em>6</em><em> </em><em>is </em><em>4</em><em> </em><em>and </em><em>the </em><em>value </em><em>of </em><em>under </em><em>root </em><em>2</em><em>5</em><em> </em><em>is </em><em>5</em><em> </em>
<em>So </em><em>the </em><em>location </em><em>of </em><em>under </em><em>root </em><em>2</em><em>0</em><em> </em><em>will </em><em>be </em><em>in </em><em>between </em><em>4</em><em> </em><em>an</em><em>d</em><em> </em><em>5</em><em> </em><em>on </em><em>the </em><em>number </em><em>line</em>
<em>.</em>
<em>.</em>
<em>.</em>
<em>Hope </em><em>it </em><em>helps</em>
The equation given in the question is
(5x + 2)/2 = 2x - 1
5x + 2 = 2(2x - 1)
5x + 2 = 4x - 2
5x - 4x = - 2 - 2
x = -4
So the value of the unknown variable comes out to be -4. Yes your calculation is correct it seems from the answer that you have given. I hope i have been able to help you in this regard.Only be careful about the cross multiplication part.
