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Vlada [557]
3 years ago
12

Find the product of 6x^2(x+4)(x-5)

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Answer:

6x⁴−6x³−120x²

Step-by-step explanation:

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2 years ago
How do you solve this problem? (x+3) cubed
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You would expand becausee it isn't equal to anything

(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one

so
for the 3rd power
(a+b)^3=1a^3+3a^2b^1+3a^1b^2+1b^3

a=x
b=3

(x+3)^3=1x^3+3x^2(3^1)+3x^1(3)^2+1(3)^3=
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7 0
3 years ago
Read 2 more answers
Please help thank you
Keith_Richards [23]

Answer:

5

alternates

Step-by-step explanation:

The series is for k = 0 to 4, so k = 0, 1, 2, 3, 4.

That is 5 terms.

-1/2 is inside the parentheses and is raised to 0, 1, 2, 3, 4.

A negative number raised to an even integer is positive.

A negative number raised to an odd integer is negative.

The sign of each term in the series alternates.

7 0
3 years ago
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