The space between the end of the wall and the towel rack will be <u>9.2 inches</u>.
<h3>What is space?</h3>
Space is the relative position of objects at a distance from one another.
In this instance, space refers to the empty area at each end of the towel rack.
<h3>Data and Calculations:</h3>
The length of the towel rack = 58.4 inches
The length of the wall = 76.8 inches
The difference between the lengths of rack and wall = 18.4 inches (76.8 - 58.4)
Since Henry wants the towel rack to be centered, the space between the end of the wall and the towel rack will be <u>9.2 inches</u> (18.4/2).
Thus, the space between the end of the wall and the towel rack will be <u>9.2 inches</u>.
Learn more about space at brainly.com/question/10558496
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<h3>Question Completion:</h3>
Let the towel rack be 58.4 inches long
1. n/2-1/3-1=1/6
n/2=1/6+1/3+1
n/2=1/6+2/6+6/6
n/2=9/6=3/2
n=3/2*2=3
check: abs(3/2-1/3)-1=1/6, abs(9/6-2/6)-1= 1/6, 7/6-1=1/6, 1/6 =1/6
3 is a root
2. -(n/2-1/3)-1=1/6
-n/2+1/3-1=1/6
-n/2-2/3=1/6
-n/2=1/6+2/3
-n/2=1/6+4/6
-n/2=5/6
n=-2*5/6=-5/3=-1 2/3
check : abs((-5/3)/2-1/3) -1=1/6
abs(-5/6-1/3) -1 =1/6, abs(-5/6-2/6) -1=1/6, abs (-7/6)-1=1/6, 7/6-1=1/6, 1/6=1/6
so -5/3 or -1 2/3 is also root
so two roots 3 and -5/3(that can be written as -1 2/3)
Combining the operations
The allowed operations are:
Add the same amount to both sides (either x's or ones)
Subtract the same amount from both sides (either x's or ones)
Multiply both sides by the same number (but not by zero)
Divide both sides by the same number (but not by zero)
(There are others, too, but they are not needed in simple equations.)
The goal is to FIRST add and subtract until we have ONLY x's (blocks) on one side and ONLY ones (circles) on the other. Then, if you have more than one block, you need to divide so as to arrive to the situation with only one block on the one side, which is the solved equation!
Answer: The first.
Step-by-step explanation: If you draw out a triangle and lable the points on each point with values from each triangle, you get J=M, K=N, and L=O. The first is the only one that proves it.
