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kap26 [50]
3 years ago
8

I need help please?!!!

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0
I think it’s b y=2 sorry if it’s wrong
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When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
3 years ago
A professor gives her 100 students an exam; scores are normally distributed. The section has an average exam score of 80 with a
frozen [14]

Answer:

6.18% of the class has an exam score of A- or higher.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 80, \sigma = 6.5

What percentage of the class has an exam score of A- or higher (defined as at least 90)?

This is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{6.5}

Z = 1.54

Z = 1.54 has a pvalue of 0.9382

1 - 0.9382 = 0.0618

6.18% of the class has an exam score of A- or higher.

4 0
3 years ago
Is 63.90 greater than 63.990
djverab [1.8K]

Answer:

63.90 is greater than63.990

3 0
3 years ago
Read 2 more answers
Solve the quadratic equation 3x²+2x-4=0
steposvetlana [31]

Answer:

Step-by-step explanation:

Hello,

\Delta = 2^2-4*3*(-4)= 4+48=52

so the two solutions are

\dfrac{-2+2\sqrt{13}}{2*3}=\dfrac{\sqrt{13}-1}{3}=0.87\\\\\dfrac{-2-2\sqrt{13}}{2*3}=-\dfrac{\sqrt{13}+1}{3}=-1.54\\\\

5 0
3 years ago
What is 39.5% written as a fraction in simplest form
White raven [17]

Answer:

\frac{79}{200}

Step-by-step explanation:

39.5% is the same as \frac{395}{1000}. You can simplify it by dividing the numerator and denominator by 5 to get \frac{79}{200}.

8 0
3 years ago
Read 2 more answers
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