Answer:
1A, 2C, 3X, 4A, 5B, 6W, 7X
Step-by-step explanation:
Im not sure about these answers, can you have the same letter for a different number?
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
Answer:
unsure but i think the first one
Step-by-step explanation:
Hey there!
First, multiply the second equation by -2 as the problem states. When you multiply the second equation by -2, you get:
-2x+4y=2
Now, add this equation to the first equation in which you simply combine like terms:
2x+y=3
+
-2x+4y=2
=
5y= 5
In conclusion, the correct answer would be the first choice.
(0,2),(-2,-1),(2,5)
-3x+2y=2
+3x +3x
2y/2=3x+2/2
y=1 1/2x+2
Plug in numbers for x then solve for y
