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3 years ago

Is (0,2) (1,0) (2,-2) (3,-4) a function

Mathematics

1 answer:

mafiozo [28]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

the X doesn't repeat

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Ok so this is so confusing The volume of water in a rectangular swimming pool can be modeled by the polynomial 2x3 _ 9x2 + 7x +

Alika [10]

The volume formula is V= l x L x H, l=width, L=Length, H= Depth, so
2x3 _ 9x2 + 7x + 6 = l x L x (2x + 1), because H=(2x + 1), so
l x L= (2x3 _ 9x2 + 7x + 6 )/ (2x + 1) = (2x3 _ 9x2 + 7x + 6 ) X [1/(2x + 1)]
case1: l= (2x3 _ 9x2 + 7x + 6 ) or L= 1/(2x + 1), case2: L= (2x3 _ 9x2 + 7x + 6 ) or l= 1/(2x + 1)
the why question:
perhaps there is similarity of value between volume and l, or volume and L

6 0

3 years ago

I need help with question 12

Llana [10]

the answer is b.............................................

3 0

3 years ago

Random sample size of 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively. T

Ugo [173]

Answer:

the mean and standard error of the mean are 200 and 2 respectively.

Step-by-step explanation:

Given that ;

the sample size n = 81

population mean μ = 200

standard deviation of the infinite population σ = 18

A population is the whole set of values, or individuals you are interested in, from an experimental study.

The value of population characteristics such as the Population mean (μ), standard deviation (σ) are said to be known as the population distribution.

From the given information above;

The sample size is large and hence based on the central limit theorem the mean of all the means is same as the population mean 200.

i.e

$\mu = \bar \mu_x$ = 200

∴ The mean = 200

and the standard error of the mean can be determined via the relation:

$\mathbf{standard \ error \ of \ mean = \dfrac{\sigma}{\sqrt {n}}}$

$\mathbf{standard \ error \ of \ mean = \dfrac{18}{\sqrt {81}}}$

$\mathbf{standard \ error \ of \ mean = \dfrac{18}{9}}$

$\mathbf{standard \ error \ of \ mean =2}$

Therefore ; the mean and standard error of the mean are 200 and 2 respectively.

6 0

3 years ago

a town is east texas received 10 inches of rain in two weeks. if it kept raining at this rate for a 31-day month, how much rain

lyudmila [28]

20 because 2 weeks is 28 day and all you have to do is do sum decimals

7 0

3 years ago

Read 2 more answers

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per in

TiliK225 [7]

Answer:

The population growth rate is 59 squirrels per year.

Step-by-step explanation:

Given:

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per individual per year and the population size is 275.

Now, to find the population growth rate.

Carrying capacity ( $K$ ) = 350.

Maximum rate ( $r_{max}$ ) = 1.0 per individual per year.

Population size ( $N$ ) = 275.

Now, to get the population growth rate we put formula:

$\frac{dN}{dT}= r_{max}\frac{K-N}{K}N$

$\frac{dN}{dT}=1.0\times \frac{350-275}{350}\times 275\\\\\frac{dN}{dT}=1.0\times \frac{75}{350}\times 275\\\\\frac{dN}{dT}=1.0\times 0.214\times 275\\\\\frac{dN}{dT}=58.85.$

So, rounding to nearest whole number of the population growth rate is 59 squirrels per year.

Therefore, the population growth rate is 59 squirrels per year.

6 0

2 years ago