Answer:
a) 20 minutes
b) 36 km/h
c) 33.67 km
d) continuous driving without any stationary phases.
Step-by-step explanation:
by the way, speed is specified in distance per time unit. in your example as km/h. and that is how your write this.
not km/h¯¹. that would be wrong, as that would actually be km×h. but you can write e.g. km×h¯¹. that is the same as km/h.
between minutes 5 and 25 there is no progress in distance. so, for these 20 minutes the bus was stationary.
in the first 5 minutes the bus drove 7-4=3 km.
so, in 5 minutes 3 km. to determine the speed we need to calculate up to see, how many km would be have driven in a full hour (60 minutes). the same factor for the time has then to be applied also to the distance to keep the ratio unchanged.
5 × x = 60
x = 12
3 × 12 = 36
so, the speed in these first 5 minutes was 3 km/5 min.
or then in km/h : 36 km/h
between the minutes 25 and 45 the bus drove with a speed of 80km/h.
and the starting point there was at 7 km.
so, the bus drove s-7 km in 20 minutes.
as before, let's first find the scaling factor to deal with a full hour instead of only 20 minutes.
20 × x = 60
x = 3
as before : distance × scaling factor = distance for km/h
(s-7) × 3 = 80
3s - 21 = 80
3s = 101
s = 33.666666666... km
Answer:
A. 0
General Formulas and Concepts:
<u>Pre-Algebra
</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I
</u>
<u>Pre-Calculus
</u>
<u>Calculus
</u>
- Derivatives
- Derivative Notation
- Derivative of csc(x) =
![\frac{d}{dx} [csc(x)] = -csc(x)cot(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcsc%28x%29%5D%20%3D%20-csc%28x%29cot%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<u />![\frac{d}{dx} [csc(x)]\\x = \frac{3 \pi}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcsc%28x%29%5D%5C%5Cx%20%3D%20%5Cfrac%7B3%20%5Cpi%7D%7B2%7D)
<u />
<u />
<u>Step 2: Differentiate</u>
- Differentiate:
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>:
- Evaluate:
Answer:
x = 9.5
Step-by-step explanation:
<h3>
Answer:</h3><h3>◎ See the attachment photo. </h3>
<h3>◎ Don't forget to thanks</h3><h3>◎ Mark as brainlist. </h3>
Answer:
<em>Hot dog sold = 33</em>
<em>Sodas Sold = 72</em>
Step-by-step explanation:
<u><em>Given:</em></u>
<em>At a hockey game a vender sold a combined total of 105 sodas and hot dogs. The number of sodas sold was 39 more than the number of hot dogs sold</em>
<u><em>To Find:</em></u>
<em>Number of soda/hot dog sold</em>
<u><em>Solve:</em></u>
<em>h + ( 39 + h ) = 105</em>
<em>h + 39 + h = 105</em>
<em>2h + 39 = 105</em>
<em>h + 19.5 = 52.5</em>
<em>h = 52.5 - 19.5 </em>
<em>This as a system does not use any inequality. "39 more than" means, +39.</em>
<em>h = 33 meaning d= 72</em>
<em />
<em>Add to check Answer:</em>
<em>33 + 72 = 105</em>
<em>Thus,</em>
<em>Hot dog sold = 33</em>
<em>Sodas Sold = 72</em>
<em />
<u><em>Kavinsky </em></u>
