Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
it is a polynomial
3a^2+a^2= 4a^2
4a^2+6
Step-by-step explanation:
3a^2 +a^2 = 4a^2+6
=4a^2+6
The negative sign show the change in direction, that is the opposite side of the value.
In the number line, 1 is the opposite of -1, that is the digit from the left side is the opposite value of the right side.
Consider an object P is moving in positive x direction than on moving the object into its opposite direction, it will move along the negative x axis.
Answer : A) -
Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?
x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6
y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6
Rectangular coordinates of the point = (x,y) =(-6,6)
Answer: Option a. (-6,6) </span>
27 because the square root of 81 is 9 and 9 times 3 is 27.
