Answer:
B(-6, 0)
Step-by-step explanation:
You want to find B such that ...
(B -A) = (3/4)(C -A) . . . . the required distance relation
4(B -A) = 3(C -A) . . . . . . multiply by 4
4B = 3C +A . . . . . . . . . . add 4A, simplify
Now, we can solve for B and substitute the given coordinates:
B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)
The coordinates of point B are (-6, 0).
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
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Answer:
yes
Step-by-step explanation:
y(x) is even or odd according as y(−x)=±y(x) . Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x). So, y is an odd function of x.
Answer:
d) The limit does not exist
General Formulas and Concepts:
<u>Calculus</u>
Limits
- Right-Side Limit:

- Left-Side Limit:

Limit Rule [Variable Direct Substitution]: 
Limit Property [Addition/Subtraction]: ![\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bx%20%5Cto%20c%7D%20%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%20%3D%20%20%5Clim_%7Bx%20%5Cto%20c%7D%20f%28x%29%20%5Cpm%20%5Clim_%7Bx%20%5Cto%20c%7D%20g%28x%29)
Step-by-step explanation:
*Note:
In order for a limit to exist, the right-side and left-side limits must equal each other.
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Find Right-Side Limit</u>
- Substitute in function [Limit]:

- Evaluate limit [Limit Rule - Variable Direct Substitution]:

<u>Step 3: Find Left-Side Limit</u>
- Substitute in function [Limit]:

- Evaluate limit [Limit Rule - Variable Direct Substitution]:

∴ Since
, then 
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
No derivation at x=3 .
only at x=3
Answer:
❥
Diameter of a circle is 8 cm. Then find out the area and perimeter of the circle.
❥
Area of circle is 50.29(≈)cm² and perimeter of circle is 25.14(≈)cm.
❥
•Given :-
Diameter of the circle = 8 cm.
•To find :-
Area and perimeter of the circle.
• Solution :-
Let the radius of the circle be r cm.
Diameter = 8 cm.
We know,
★
So, Radius (r) = 8/2= 4 cm.
We know,
★
Area of circle= πr²
→Area of circle=
→Area of circle=
→Area of circle= 50.29(≈)cm²
____________________________
We know,
★
Perimeter of circle= 2πr
→ Perimeter of circle=
→Perimeter of circle=25.14(≈)cm