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WITCHER [35]
3 years ago
5

What is the percent yield of titanium (IV) oxide, if 10.2 g are formed when 25.7

Chemistry
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

Percent yield = 91%

Explanation:

Given data:

Percent yield of TiO₂ = ?

Actual yield = 10.2 g

Mass of TiCl₄ react = 25.7 g

Solution:

Chemical equation:

TiCl₄  + O₂   →    TiO₂  + 2Cl₂

Number of moles of TiCl₄:

Number of moles = mass/molar mass

Number of moles = 25.7 g/ 189.7 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of  TiCl₄  and TiO₂.

                       TiCl₄           :            TiO₂

                         1                :              1

                         0.14           :              0.14

Theoretical yield:

Mass = number of moles ×molar mass

Mass = 0.14 mol × 79.86 g/mol

Mass = 11.2 g

Percent yield:

Percent yield = [actual yield / theoretical yield ]  × 100

Percent yield = [10.2 g / 11.2 g ]× 100

Percent yield = 91%

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Answer:

The correct answer is :

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2) Tollen's test

Explanation:

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2. Tollen's test is also a test that help in identifying the presence of aldehyde as the Tollen's reagents oxidizes aldehydes where ketones as they lack hydrogen in them.

Thus, the correct answer is : 1) Fehling's test,

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7 0
3 years ago
Give the following reaction: ammonium nitrate—> dinitrogen monoxide + water.
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Answer:

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Explanation:

Step 1: Write the balanced equation

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0.280 mol × 6.02 × 10²³ molecules/1 mol = 1.69 × 10²³ molecules

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Answer:

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Explanation:

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