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3 years ago

What is the percent yield of titanium (IV) oxide, if 10.2 g are formed when 25.7

Chemistry

1 answer:

yawa3891 [41]3 years ago

7 0

Answer:

Percent yield = 91%

Explanation:

Given data:

Percent yield of TiO₂ = ?

Actual yield = 10.2 g

Mass of TiCl₄ react = 25.7 g

Solution:

Chemical equation:

TiCl₄ + O₂ → TiO₂ + 2Cl₂

Number of moles of TiCl₄:

Number of moles = mass/molar mass

Number of moles = 25.7 g/ 189.7 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of TiCl₄ and TiO₂.

TiCl₄ : TiO₂

1 : 1

0.14 : 0.14

Theoretical yield:

Mass = number of moles ×molar mass

Mass = 0.14 mol × 79.86 g/mol

Mass = 11.2 g

Percent yield:

Percent yield = [actual yield / theoretical yield ] × 100

Percent yield = [10.2 g / 11.2 g ]× 100

Percent yield = 91%

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3 years ago

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2 years ago

What is the mass (in grams) of 6.78 moles of dinitrogen pentoxide

WINSTONCH [101]

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The answer is:

There are 732.24 grams of Dinitrogen Pentoxide $N_{2}O_{5}$ in 6.78 moles of the same compound.

The dinitrogen pentoxide, or nitrogen pentoxide, is a rare salt that consists of anion and cations, and it's an important compound when preparing some kinds of explosives.

So, to answer the question, first, need to look for the molecular formula of the dinitrogen pentoxide, then, use it to calculate the mass in gram of 6.78 moles of the same compound.

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