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2 years ago

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The Statue of Liberty is composed of copper. The smallest particle of any amount of copper is A) an atom. B) an element. C) a co

mpound. Eliminate D) a molecule.

1 answer:

Lina20 [59]2 years ago

5 0

an atom because its the smallest thing in the entire world and in all orgnaisms

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Atom with three<br> full orbits<br> What is it

nekit [7.7K]

Answer:

Boron. The answer is boron.

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3 years ago

Read 2 more answers

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO4. (a) Write the balanced chemical equ

NISA [10]

Answer:

a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂

b) Ni(OH)₂

c) KOH

d) 0.927 g

e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M

Explanation:

a) The equation is:

2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂ (1)

b) The precipitate formed is Ni(OH)₂

c) The limiting reactant is:

$n_{KOH} = V*M = 100.0 \cdot 10^{-3} L*0.200 mol/L = 0.020 moles$

$n_{NiSO_{4}} = V*M = 200.0 \cdot 10^{-3} L*0.150 mol/L = 0.030 moles$

From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:

$n = \frac{2}{1}*0.030 moles = 0.060 moles$

Hence, the limiting reactant is KOH.

d) The mass of the precipitate formed is:

$n_{Ni(OH)_{2}} = \frac{1}{2}*n_{KOH} = \frac{1}{2}*0.020 moles = 0.010 moles$

$m = n*M = 0.010 moles*92.72 g/mol = 0.927 g$

e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:

$C_{K^{+}} = \frac{2*\frac{1}{2}*n_{KOH}}{V} = \frac{0.020 moles}{0.300 L} = 0.067 M$

$C_{SO_{4}^{2-}} = \frac{\frac{1}{2}*n_{KOH + (0.03 - 0.01)}}{V} = \frac{0.030 moles}{0.300 L} = 0.1 M$

$C_{Ni^{2+}} = \frac{0.020 moles}{0.300 L} = 0.067 M$

I hope it helps you!

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3 years ago

After careful analysis, an electromagnetic wave is found to have a frequency of 7.8 x 10^6 Hz. What is the speed of the wave?

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Explanation:

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Which is a type of star system?

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When a piece of metal A is placed in a solution containing ions of metal B, metal B plates out on the piece of A.(c) Which metal

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Zinc is no longer the positive electrode because copper has a more positive (higher) value than zinc (anode). The anode value is reduced by the potential of the other electrode.

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In a galvanic (voltaic) cell, the cathode is regarded as positive and the anode as negative. This seems reasonable given that the cathode is where electrons flow from the anode, which is where they originate.

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1 year ago