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3 years ago

Please help! If the m = 1/2 and the b = -2, then the linear equation is:

Mathematics

2 answers:

hoa [83]3 years ago

8 0

Y=1/2x-2 is the correct answer

Vsevolod [243]3 years ago

7 0

Answer:

y=1/2x-2

you write it in y=mx+b form

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A computer virus infects files very quickly. The number of files triples every minute. After the first minute, five files are in

cupoosta [38]

Answer:

Step-by-step explanation:

The answer is C because r =3 I got that because it says triples. a=5 it comes from when it says five files are infected. an=3an-1. an=5(3)n-1. Hope this helps!

8 0

3 years ago

Will mark brainliest :)

jek_recluse [69]

Answer:

Step-by-step explanation:

The equation of the parabola is of the form

y = ax² + c ( where c is the y- intercept )

Here c < 0

Since the parabola has a maximum value and opens down then a < 0

Thus the only equation that could represent this parabola is

y = - x² - 3 → D

3 0

3 years ago

Solve the equation -2y+4=8y-6

Sergeeva-Olga [200]

Answer:

y = 1

Step-by-step explanation:

-2y + 4 = 8y - 6

First, add 2y to both sides to cancel out the letter variable.

4 = 10y - 6

Second, add 6 to both sides to cancel out the number variable.

10 = 10y

Finally, divide both sides by 10

y = 1

Tip: Be sure to always keep the letter on the left side of the answer.

4 0

3 years ago

Read 2 more answers

surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo

balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

Tan(58°)*100m = h1 = 160m.

The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be:

h2 - h1 = 196.3m - 160m = 36.3m

6 0

3 years ago

Issa jogged 2/3 of the way home from school .Then he was tired ,so he walked the remaining 3,200 m how many kilometers did he tr

MissTica

Answer:

9.6 km

Step-by-step explanation:

Issa jogged 2/3 of the way home from school.

Then he was tired, so he walked the remaining 3200 m.

In other words, the remaining 3200 m is 1/3 of the way from school to home.

Let the distance from school to home be x. Therefore:

$\frac{1}{3} * x = 3200\\\\=> x = 3200 * 3 \\\\x = 9600 m$

Therefore, from school to home he traveled 9600 m.

To put this is kilometres:

1000 m = 1 km

9600 m = 9600 / 1000 = 9.6 km

He traveled 9.6 km from school to home.

4 0

4 years ago