Which of the following points lies on the line y=x?(-4,4)(2,-2)(-4,-4)-2,2

Mathematics

1 answer:

marshall27 [118]2 years ago

7 0

The answer is (-4,-4) because y has to equal x, the first -4 is the x and the second one is the y

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Suppose given △ABD and △CBD.

patriot [66]

Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that $\frac{AD}{AB}=\frac{DC}{CB}$

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

In ΔADB, AE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

$\frac{DE}{EB}=\frac{AD}{AB}$ → (1)

In ΔDCB, CE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.

$\frac{DE}{EB}=\frac{CD}{CB}$ → (2)

From equation (1) and (2), we get

$\frac{AD}{AB}=\frac{CD}{CB}$

Hence Proved.

5 0

2 years ago

Please HELP! I DON'T KNOW HOW CAN I SOLVE THIS

Wewaii [24]

Answer:

Step-by-step explanation:

The Pythagorean Theorem:

$leg^2+leg^2=hypotenuse^2\to a^2+b^2=c^2$

$41.\\\\a=1,\ b=1,\ c=x\\\\x^2=1^2+1^2\\\\x^2=1+1\\\\x^2=2\to x=\sqrt2$

$42.\\a=1, b=2,\ c=x\\\\x^2=1^2+2^2\\\\x^2=1+4\\\\x^2=5\to x=\sqrt5$

$43.\\a=3,\ b=x,\ c=5\\\\3^2+x^2=5^2\\\\9+x^2=25\qquad\text{subtract 9 from both sides}\\\\x^2=16\to x=\sqrt{16}\to x=4$

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