1. Find the lengths of the diagonals of rectangle QRST , Given that QS = 6X+3 and RT = 8X-1

Mathematics

2 answers:

Bezzdna [24]3 years ago

8 0

For the lengths, Qs and RT= 15

Greeley [361]3 years ago

5 0

Answer:

1. QS and RT= 15

2. Im not positive but I think it's TQ=18

Step-by-step explanation:

For question 1, you would do 6x+3=8x-1 and solve to get the result of x=2

Then you'd plug in 6 and get QS and RT=15

For the second one I am unsure because I wasn't positive how to solve but it seems like the side RQ might be 1/2 of TQ. Sorry if thats wrong I can try and help more if you need

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3 years ago

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$