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Schach [20]
3 years ago
15

Two angles in a triangle have measures of 25° and 55°.

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

Answer:

B) 100

Step-by-step explanation:

All 3 interior angles of a triangle add up to 180 so:

x + 25 + 55 = 180

x + 80 = 180

x = 180 - 80

x = 100

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During one month, a homeowner used 500 units of electricity and 100 units of gas for a total cost of $333. The next month, 400 u
Mice21 [21]

Answer: the cost per unit of gas is $0.28

Step-by-step explanation:

Let x represent the cost per unit of electricity.

Let y represent the cost per unit of gas.

During one month, a homeowner used 500 units of electricity and 100 units of gas for a total cost of $333. This is expressed as

500x + 100y = 333 - - - -- - -- - -- -1

The next month, 400 units of electricity and 150 units of gas were used for a total cost of $286. This is expressed as

400x + 150y = 286 - - - - - - - - - --2

Multiplying equation 1 by 400 and equation 2 by 500, it becomes

200000x + 40000y = 133200

200000x + 75000y = 143000

Subtracting, it becomes

- 35000y = - 9800

y = - 9800/- 35000

y = 0.28

Substituting y = 0.28 into equation 2, it becomes

400x + 150 × 0.28 = 286

400x = 286 - 42 = 244

x = 244/400 = 0.61

7 0
3 years ago
Help me do the math and the steps to do or to get to the answer
Hunter-Best [27]
Pink:
10 * 10 = 100

Blue:
10 * 4 = 40

Purple:
9 * 10 = 90

Green:
4 * 9 = 36

Add them all together.
100 + 90 + 40 + 36 = 266

Have an awesome day! :)
5 0
3 years ago
Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
A sector has a central angle of 3/4 π radians and an area of 12 square units. Find the area of the circle.
stich3 [128]

Answer:

9

Step-by-step explanation:

3/4 radians x12=9

8 0
3 years ago
Given : ∠MNQ AND ∠ONP are vertical angles <br> Prove : ∠MNQ ≅ ∠ ONP
fgiga [73]

Answer:

They are supplementary, and since they are congruent and vertical, they fall on the same line, meaning that they are linear

Step-by-step explanation:

6 0
3 years ago
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